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kherson [118]
3 years ago
15

HELPPPPPPPPPPPPPPPPPPP ASAP!!!!!!

Mathematics
1 answer:
krok68 [10]3 years ago
7 0

Answer:

there is 8 quadrilateral shapes

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Find the equation of a line perpendicular to y = -3 passing through the coordinate (2, 6).
Vlad [161]

Answer:

for two lines to be perpendicular m2 = -1/m2

using the formula y= mx+c

m1 = 0

for the lines to be perpendicular to each other(m2 = -1/0 )

Note: -1/0 is undefined

using the formula y-y1 = m(x-x1)

y -6 = -1/0(x-2)

cross multiply

0 = -1(x-2)

0 = -x+2

x =2(equation of the line)

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2 years ago
What is the equation of the line that passes through the point (-2, 6) and has a slope of -3?
poizon [28]

Answer:

y=-3x

Step-by-step explanation:

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3 years ago
Choose the correct label for the solution to each system of equations from the drop-down menus.
vovikov84 [41]

Answer: left one is no solution and right one is infinite solutions

explanation: the left one the lines don’t touch at all which has no solution and the right one means that both lines are on top of each other

5 0
3 years ago
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When consumers apply for credit, their credit is rated using FICO (Fair, Isaac, and Company) scores. Credit ratings are given be
Flura [38]

Answer:

a) The 99% confidence interval would be given by (589.588;731.038)

b) If we see the confidence interval the 620 is included on the interval we don't have enough evidence to reject the rating is 620. But since we need a score that at least 620 and our lower limit is 589.588 we cant conclude that all the clients would have a score that at least of 620.  

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The data is:

661 595 548 730 791 678 672 491 492 583 762 624 769 729 734 706

Part a

Compute the sample mean and sample standard deviation.  

In order to calculate the mean and the sample deviation we need to have on mind the following formulas:  

\bar X= \sum_{i=1}^n \frac{x_i}{n}  

s=\sqrt{\frac{\sum_{i=1}^n (x_i-\bar X)}{n-1}}  

=AVERAGE(661, 595, 548, 730, 791, 678, 672, 491 ,492, 583, 762 ,624 ,769, 729, 734, 706)

On this case the average is \bar X= 660.313

=STDEV.S(661, 595, 548, 730, 791, 678, 672, 491 ,492, 583, 762 ,624 ,769, 729, 734, 706)

The sample standard deviation obtained was s=95.898

Find the critical value t* Use the formula for a CI to find upper and lower endpoints

In order to find the critical value we need to take in count that our sample size n =16<30 and on this case we don't know about the population standard deviation, so on this case we need to use the t distribution. Since our interval is at 99% of confidence, our significance level would be given by \alpha=1-0.99=0.01 and \alpha/2 =0.005. The degrees of freedom are given by:

df=n-1=16-1=15

We can find the critical values in excel using the following formulas:

"=T.INV(0.005,15)" for t_{\alpha/2}=-2.95

"=T.INV(1-0.005,15)" for t_{1-\alpha/2}=2.95

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}  

And if we find the limits we got:

660.313- 2.95\frac{95.898}{\sqrt{16}}=589.588  

[tex]660.313+ 2.95\frac{95.898}{\sqrt{16}}=731.038/tex]  

So the 99% confidence interval would be given by (589.588;731.038)

Part b

If we see the confidence interval the 620 is included on the interval we don't have enough evidence to reject the rating is 620. But since we need a score that at least 620 and our lower limit is 589.588 we cant conclude that all the clients would have a score that at least of 620.  

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3 years ago
(11 BRAINLY POINTS!!) Which of the following numbers can be expressed as a decimal that terminates?
balu736 [363]

Answer:

I believe that it is b

Step-by-step explanation:

But correct me if i am wrong! Have a nice day!

4 0
3 years ago
Read 2 more answers
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