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3 years ago

1. What causes charge in the motion of the object

Mathematics

2 answers:

Murrr4er [49]3 years ago

6 0

Answer:

volume

Step-by-step explanation:

imjust joking u need points

Assoli18 [71]3 years ago

3 0

1. An object at rest has zero velocity - and (in the absence of an unbalanced force) will remain with a zero velocity. Such an object will not change its state of motion (i.e., velocity) unless acted upon by an unbalanced force

2. When physicists speak about an object's velocity, they are talking not only about the object's speed but also about the direction in which it's moving. Similarly, force has a directional component as well as a quantitative one -- a force directly opposing an object's velocity has a different effect on the object than a force acting at right angles to its motion. In mathematical terms, force, velocity and acceleration -- which is the rate of change of velocity produced by a force -- are "vector" quantities, which is a term that implies their directional component.

Hope this helps!

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PLSS HELP ASAP TYSM <33 SORRY I COULDN'T FIND SCIENCE LOLL

dimaraw [331]

Answer:

Rock D.

Step-by-step explanation:

We can assume that the force that the catapult does is always the same.

So, here we need to remember Newton's second law:

F = m*a

force equals mass times acceleration.

Where acceleration is the rate of change of the velocity.

So, if we want the rock to hit closer to the catapult, the rock must be less accelerated than rock B.

So, we can rewrite:

a = F/m

So, as larger is the mass of the rock, smaller will be the acceleration of the rock after it leaves the catapult (because the mass is in the denominator). So if we want to have a smaller acceleration, we need to choose a rock with a larger mass than rock B.

Assuming that the mass depends on the size, the only one that has a mass larger than rock B is rock D.

So we can assume that rock D is the correct option.

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3 years ago

-5x-2y= −5x−2y= \,\,-40 −40 y= y= \,\,2x+2 2x+2

Eva8 [605]

Answer: look at the ss :))

Step-by-step explanation:

4 0

3 years ago

PLS HELP ME!! STATE THE DOMAIN AND RANGE OF EACH RELATION AND WHETHER ITS A FUNCTION

muminat

Domain is everything below 0. Range is all real numbers. It is a function as it passes the vertical line test.

5 0

3 years ago

A log is floating on swiftly moving water. A stone is dropped from rest from a 50.8-m-high bridge and lands on the log as it pas

TiliK225 [7]

Answer:

Horizontal distance between the log and the bridge when the stone is released = 17.24 m

Step-by-step explanation:

Height of bridge, h = 50.8 m

Speed of log = 5.36 m/s

We need to find the horizontal distance between the log and the bridge when the stone is released, for that first we need to find time taken by the stone to reach on top of log,

We have equation of motion. s = ut + 0.5 at²

Initial velocity, u = 0 m/s

Acceleration, a = 9.81 m/s²

Displacement, s = 50.8 m

Substituting,

s = ut + 0.5 at²

50.8 = 0.5 x 9.81 x t²

t = 3.22 seconds,

So log travels 3.22 seconds at a speed of 5.36 m/s after the release of stone,

We have equation of motion. s = ut + 0.5 at²

Initial velocity, u = 5.36 m/s

Acceleration, a = 0 m/s²

Time, t = 3.22 s

Substituting,

s = ut + 0.5 at²

s = 5.36 x 3.22 + 0.5 x 0 x 3.22²

s = 17.24 m

Horizontal distance between the log and the bridge when the stone is released = 17.24 m

3 0

3 years ago

I request assistance on answering this question

Ket [755]

The answer is going to be6/8

6 0

3 years ago