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Ahat [919]
3 years ago
9

The average cost of online photos decreased

Mathematics
1 answer:
SCORPION-xisa [38]3 years ago
6 0

Answer:

The average rate of change is -0.034 which means that the decrease is -0.034 in the cost of per print per year

Step-by-step explanation:

Given that

Price of print in 2002 = p1 =$0.50

Price of print in 2013 = p2 =$0.13

y1 = 2002

y2 = 2013

The rate of change is given by the formula:

r = \frac{decrease}{run}

Here decrease is the change in price and run is the difference in years.

Mathematically, it can be written as:

r = \frac{p_2-p_1}{y_2-y_1}

Putting the values

r =\frac{0.13-0.50}{2013-2002}\\r = \frac{-0.37}{11}\\r =-0.0336\\r = -0.034

Hence,

The average rate of change is -0.034 which means that the decrease is -0.034 in the cost of per print per year

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The markup of a computer is $3,237.50. The markup rate is 75%. What is the selling price?
Kaylis [27]

The applicable relation is

... selling price = cost + markup

You have not said what the base is for the markup percentage. If markup is 75% of the cost, then we have

... markup = 0.75×cost

... cost = markup/0.75 = 3237.50/0.75 = 4316.67

Then the selling price is

... selling price = $4316.67 +$3237.50 = $7,554.17

_____

If the markup is 75% of the selling price, then we have

... markup = 0.75×selling price

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3 years ago
PLEASE ELP ME ITS URGENT!!! 25 POINTS!!!!!<br> Write 2.4 × 1012 in standard notation.
Svet_ta [14]

Answer:

2,400,000,000,000

Step-by-step explanation:

2.4 x 10^12 means that the decimal point is moved 12 places to the right (hence the power of 12)

So by moving the decimal point 12 times you get this: 2,400,000,000,000

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Use photomath app

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A golfer takes a swing from a hill twenty feet above the cup with an initial upwards velocity of 76 feet per second. How long do
jeka94

Answer:

t = 5 seconds

Step-by-step explanation:

A golfer takes a swing from a hill twenty feet above the cup with an initial upwards velocity of 76 feet per second.

We need to find how long does it take the ball to land on the ground near the cup.

The equation for the path of the ball is given using second equation of kinematics as follows :

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Neglecting negative value,

It will take 5 seconds for the ball to land on the ground near the cup.

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3 years ago
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