Answer:
5(5k²+6)(4k-3)
Step-by-step explanation:
100k³ - 75k² + 120k - 90
Take 5 common above:
= 5(20k³ - 15k² + 24k - 18) ------- eq1
First let simplify 20k³ - 15k² + 24k - 18
= (20k³ - 15k²) + (24k - 18) ---------eq2
Factor out 6 from 24k - 18 :
6(4k-3)
Factor out 5k² from (20k³ - 15k²):
5k²(4k -3)
eq2 becomes: = 6(4k-3) + 5k²(4k -3)
Factor out common term 4k-3
(6+ 5k²)(4k -3) or (5k²+6)(4k-3)
Thus eq1 becomes:
5(5k²+6)(4k -3)
I’m not 100% true but i think it’s false, true, true :)
Using sampling concepts, the population and the sample are given as follows:
d. population: 6,000 batches of 100 cards sample: every 100th batch.
<h3>What is sampling?</h3>
It is a common statistics practice, when we want to study something from a population, we find a sample of this population, which is a <u>group containing elements of a population</u>. A sample has to be representative of the population, that is, it has to involve all segments of the population.
For example:
I want to estimate the proportion of New York state residents who are Buffalo Bills fans. So I ask, lets say, 1000 randomly selected New York state residents whether they are Buffalo Bills fans, and then:
- The population is: All New York State residents.
- The sample is the 1000 randomly selected New York state residents.
Hence, in the situation described the population is the 6,000 batches of 100 cards, while the sample is every 100th batch, hence option d is correct.
More can be learned about sampling concepts at brainly.com/question/25122507
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