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maxonik [38]
3 years ago
15

Find a solution for the equation. Assume that all angles are a cute angles. tan(3Y +32) = cot(Y+32°)

Mathematics
1 answer:
Lera25 [3.4K]3 years ago
5 0

9514 1404 393

Answer:

  Y = 6.5°

Step-by-step explanation:

We know that tan(x) = cot(90°-x), so we could rewrite the equation as ...

  cot(90 -(3Y+32)) = cot(Y+32)

  58 -3Y = Y +32

  26 = 4Y

  6.5 = Y

One solution is Y = 6.5°.

_____

Additional solutions are found at integral multiples of 45° added to this value.

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Mr. Kelly bought a 50-pound bag of potatoes for $37.00. What is the cost of the potatoes per pound?
jek_recluse [69]

Answer:

$0.74 per pound of potatoes

Step-by-step explanation: $37 divided by 50 pounds (37/50) = 0.74

6 0
3 years ago
A block of cheese has a volume of 280 cm3 and a mass of 230 g.
Leviafan [203]

Answer:

2.7g/cm^3

step-by-step explanation:

6 0
3 years ago
Solve for x<br><img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B4x%20-%206%7D%7B4%7D%20%20%3D%20%20%5Cfrac%7B2x%20%2B%205%7D%7B3%7
Marizza181 [45]

Answer:

x = 9.5

Step-by-step explanation:

Given

\frac{4x-6}{4} = \frac{2x+5}{3} ( cross- multiply )

3(4x - 6) = 4(2x + 5) ← distribute parenthesis on both sides

12x - 18 = 8x + 20 ( subtract 8x from both sides )

4x - 18 = 20 ( add 18 to both sides )

4x = 38 ( divide both sides by 4 )

x = \frac{38}{4} = 9.5

6 0
3 years ago
Find the length and width of a rectangle that has the given area and a minimum perimeter. Area: 162 square feet
Gnom [1K]

Answer:

The width and length of rectangle is 12.728 m

Step-by-step explanation:

Let the length of the rectangle = L

let the width of the rectangle = W

The subjective function is given by;

F(p) = 2(L + W)

F = 2L + 2W

Area of the rectangle is given by;

A = LW

LW = 162 ft²

L = 162 / W

Substitute in the value of L into subjective function;

f = 2l + 2w\\\\f = 2(\frac{162}{w} )+2w\\\\f = \frac{324}{w} + 2w\\\\\frac{df}{dw} = \frac{-324}{w^2} +2\\\\

Take the second derivative of the function, to check if it will given a minimum perimeter

\frac{d^2f}{dw^2}= \frac{648}{w^3} \\\\Thus, \frac{d^2f}{dw^2}>0, \ since,\frac{648}{w^3} >0 \ (minimum \ function \ verified)

Determine the critical points of the first derivative;

df/dw = 0

\frac{-324}{w^2} +2 = 0\\\\-324 + 2w^2=0\\\\2w^2 = 324\\\\w^2 = \frac{324}{2} \\\\w^2 = 162\\\\w= \sqrt{162}\\\\w = 12.728 \ m

L = 162 / 12.728

L = 12.728 m

Therefore, the width and length of rectangle is 12.728 m

3 0
3 years ago
Is (3,1) a solution of the equation y=-x+3
kogti [31]

no i don't think so the answer will be (3,0)

3 0
3 years ago
Read 2 more answers
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