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2 years ago

What is the slope of this line??

Mathematics

1 answer:

zlopas [31]2 years ago

3 0

The slope is -1/2x. The equation of this graph would be y=-1/2x+5.5

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List below are the speeds (mi/h) measured from southbound traffic on I-280 near Cupertino, CA. Use the sample data to construct

zheka24 [161]

Answer:

The 99% confidence interval of the population standard deviation is 1.7047 < σ < 7.485

Step-by-step explanation:

Confidence interval of standard deviation is given as follows;

$\sqrt{\dfrac{\left (n-1 \right )s^{2}}{\chi _{1-\alpha /2}^{}}}< \sigma < \sqrt{\dfrac{\left (n-1 \right )s^{2}}{\chi _{\alpha /2}^{}}}$

s = $\sqrt{\dfrac{\Sigma (x - \bar x)^2}{n - 1} }$

Where:

$\bar x$ = Sample mean

s = Sample standard deviation

n = Sample size = 7

χ = Chi squared value at the given confidence level

$\bar x$ = ∑x/n = (62 + 58 + 58 + 56 + 60 +53 + 58)/7 = 57.857

The sample standard deviation s = $\sqrt{\dfrac{\Sigma (x - \bar x)^2}{n - 1} }$ = 2.854

The test statistic, derived through computation, = ±3.707

Which gives;

$C. I. = 57.857 \pm 3.707 \times \dfrac{2.854}{\sqrt{7} }$

$\sqrt{\dfrac{\left (7-1 \right )2.854^{2}}{16.812}^{}}}< \sigma < \sqrt{\dfrac{\left (7-1 \right )2.854^{2}}{0.872}}$

1.7047 < σ < 7.485

The 99% confidence interval of the population standard deviation = 1.7047 < σ < 7.485.

7 0

3 years ago

Helloo!!! please help me on this !!!!

ivann1987 [24]

It is given that ️PQR & ️UVW are congruent to each other. According to CPCT, the corresponding angles in 2 triangles willl have the same measure. So, ∠R = ∠W, i.e, (10x - 18)° = 8x°

$\mathfrak{10x - 18 = 8x}$

$\mathfrak{10x - 8x = 18}$

$\mathfrak{2x = 18}$

$\mathfrak{x = \dfrac{18}{2}}$

$\underline{\mathfrak{x = 9}}$

Measure of ∠R :

$\mathfrak{8x}$

$\mathfrak{8(9)}$

$\boxed{\mathfrak{72^{\circ}}}$

ღ ꪑ꠸᥅ꫀꪊ

7 0

2 years ago

Solve each question. Solve for x

mamaluj [8]

I hope this helps you

3 0

2 years ago

Use partial fraction expansion to evaluate: LaTeX: \int\frac{x-1}{x^2+3x+2}dx ∫ x − 1 x 2 + 3 x + 2 d x a. LaTeX: -2\ln\left|x+1

ohaa [14]

$\frac{x-1}{x^2+3x+2}\\\frac{x-1}{(x+1)(x+2)}\\\frac{x-1}{(x+1)(x+2)}=\frac{A}{x+2}+\frac{B}{x+1}\\x-1=A(x+1)+B(x+2)\\\\\text{ Let } x=-1 \text{ then } -2=A(0)+B(-1+2) \text{ which means } B=-2\\\\\text{ Instead of choose } x \text{ to be -1, let's now set it equal to -2 to find } A\\\\-3=A(-1)+B(-2+2)\\-3=-A\\A=3\\\\ \text{ So your integral becomes } \\\int \frac{3}{x+2} dx+\int \frac{-2}{x+1} dx\\3 \ln|x+2|-2\ln|x+1|+C\\\\or\\-2\ln|x+1|+3\ln|x+2|+C$

8 0

3 years ago

Can someone help me on this

Ierofanga [76]

1/2 of angle D is given as 32 degrees.

The 3 inside angles need to add up to 180 degrees.

Angle B is a right angle, which is 90.

Angle C = 180 - 90 - 32 = 58 degrees.

8 0

3 years ago