Find the Greatest Common Factor of the Numerator and Denominator

Mathematics

1 answer:

myrzilka [38]3 years ago

5 0

Answer:

Step-by-step explanation:

i fink no very is not good becauese it nit nivr so i thimk

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I have math question can someone help me quickly?

olga55 [171]

What is the question?

7 0

3 years ago

Subtract and simplify 10 - 5 1/8

asambeis [7]

10 - 5 1/8

Convert 5 1/8 into an improper fraction.

We do this by multiplying the denominator to the whole number and adding it to the numerator, and wee keep the denominator.

8 * 5 = 40 + 1 = 41/8

10 - 41/8

Convert 10 to a denominator of 8:

10 * 8 = 80
1 * 8 = 8

80/8 = 41/8

Subtract the numerators together and keep the denominator:

39/8

Convert to a mixed number:

4 7/8

3 0

3 years ago

Read 2 more answers

Solve for x.<br> Sqrt8 (Sqrt2 - x) = 11

Alexus [3.1K]

Answer: $\frac{-7\sqrt{2} }{4}$

Step-by-step explanation:

So first, let's get rid of the parentheses. We can multiply it out to get $\sqrt{16}-x\sqrt{8} =11$ . We know that the square root of 16 is ±4, so now our equation is ±4 - $x\sqrt{8}$ =11. I'm guessing since the problem only has one solution it's most likely only positive 4, so let's revise our equation to 4 - $x\sqrt{8}$ =11. We can use inverse operations to make the a little easier to solve: -7= $x\sqrt{8}$ . We divide both sides by $\sqrt{8}$ to get $\frac{-7}{\sqrt{8} } =x$ , which we can rationalize (remove the square root from the denominator so that it's a proper answer) by multiplying by $\frac{\sqrt{8} }{\sqrt{8} }$ (which is equal to one so we can use it) which is equal to $\frac{-7\sqrt{8} }{8}$ . Let's finish this by simplifying it. $\sqrt{8} =2\sqrt{2}$ (2x $2^{2}$ ). We can simplify it further by simplifying the 2, making it $\frac{-7\sqrt{2} }{4}$ .