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lesya692 [45]
2 years ago
11

What is the value of x ?

Mathematics
2 answers:
Sliva [168]2 years ago
8 0

Answer:

28.61258...

Step-by-step explanation:

Don't really know how to explain this over a computer, but it is correct.

Hope that this helps!

4vir4ik [10]2 years ago
4 0

Answer:

What is the value of x?

Whenever we have a problem to solve we assume the unknown quantity(or value to be identified) as x. This is just a convention followed in algebra by using a variable to denote the unknown quantity and then arrive at the solution.

What is the value of X?

What's the value of X?

X + X = X, what is the value of X?

What is the value of x ? How can I find it?

Do you know the value of x?

Value of X can be any numerical value or anything but depends solely on your question .But I find no question ok lets take an example .

If an equation is given ,

X+2=4

=> X=4–2

=>X=2

We X's value as 2 .

Now another ,

X + Y = 5 , 2X + 5Y = 10

Now taking first equation

X = 5-Y ………………………..(1)

Now taking second equation

X= 10–5Y/2…………………(2)

Now,

2(5-Y) = 10–5Y

=> 10–2Y = 10–5Y

=> 2Y = 5Y

Y has no value here because this equation not correctly represented .

Hence ,

We conclude the value of X varies with equation .

Thank You ,

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Solve 5x^2 - 7x + 2 = 0 by completing the square.
Reika [66]

Answer:  The correct option is (c) \dfrac{49}{100}.

Step-by-step explanation:  We are given to solve the following quadratic equation by the method of completing the square:

5x^2-7x+2=0~~~~~~~~~~~~~~~~~~~(i)

Also, we are to find the constant added on both sides to form the perfect square trinomial.

We have from equation (i) that

5x^2-7x+2=0\\\\\Rightarrow x^2-\dfrac{7}{5}x+\dfrac{2}{5}=0\\\\\\\Rightarrow x^2-2\times x\times \dfrac{7}{10}+\left(\dfrac{7}{10}\right)^2+\dfrac{2}{5}=\left(\dfrac{7}{10}\right)^2\\\\\\\Rightarrow \left(x-\dfrac{7}{10}\right)^2=\dfrac{49}{100}-\dfrac{2}{5}\\\\\\\Rightarrow  \left(x-\dfrac{7}{10}\right)^2=\dfrac{49-40}{100}\\\\\\\Rightarrow  \left(x-\dfrac{7}{10}\right)^2=\dfrac{9}{100}\\\\\\\Rightarrow x-\dfrac{7}{10}=\pm\dfrac{3}{10}\\\\\\\Rightarrow x=\pm\dfrac{3}{10}+\dfrac{7}{10}.

So,

x=\dfrac{3}{10}+\dfrac{7}{10},~~~~~~~~x=-\dfrac{3}{10}+\dfrac{7}{10}\\\\\\\Rightarrow x=\dfrac{10}{10},~~~~~~~~\Rightarrow x=\dfrac{-3+7}{10}\\\\\\\Rightarrow x=1,~-\dfrac{2}{5}.

Thus, the required solution is x=1,~-\dfrac{2}{5}. and the value of the constant added is \dfrac{49}{100}.

Option (c) is correct.

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3 years ago
A.) $405.00
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$450 since first month was free if it wasn’t free it would’ve been $495
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