Answer:
<u>D) (f o g)(x) = 10x² - 60x + 93</u>
Step-by-step explanation:
f(x) = 10x² + 3
g(x) = x - 3
⇒ (f o g)(x)
⇒ f(x - 3)
⇒ f(x - 3) = 10(x - 3)² + 3
⇒ f(x - 3) = 10(x² - 6x + 9) + 3
⇒ f(x - 3) = 10x² - 60x + 90 + 3
⇒ <u>(f o g)(x) = 10x² - 60x + 93</u>
Answer:
<h3>
The width (side perpedicular to the barn):
<u>x = 8 m</u></h3><h3> The lenght (side parallel to the barn):
<u>y = 16 m</u> </h3>
Step-by-step explanation:
x - the width of the barn
She has 32 m of fencing so for the lenght remain (32-2x) m of fencing:
y = 32 - 2x
Area of the fencing: A = x•y
A(x) = x•(32 - 2x)
A(x) = -2x² + 32x ← quadratic function
The maximum value of quadratic function occurs at: 
a = -2, b = 32

32-2x = 32 - 2•8 = 16
Answer:1.75t + 3.50 ≤ 20
Step-by-step explanation:hope this helps :)
Answer:
x=1/4
y = -2
(1/4, -2)
b
Step-by-step explanation:
4x -y =3
y =-8x
substitute y =-8x into the first equation. Everywhere you see y put 8x
4x -y =3
4x - (-8x) =3
4x+8x=3
combine like terms
12x = 3
divide by 12
12x/12x = 3 /12
x = 1/4
now we need to find y
y = -8x
y = -8 * 1/4
y = -2