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Vsevolod [243]
3 years ago
12

Michelle flips a penny four times, and it lands heads up all four times. On her fifth flip, what is the probability that the pen

ny will land tails up? Explain.
Mathematics
1 answer:
snow_tiger [21]3 years ago
8 0

Answer:

1/2

Step-by-step explanation:

theoretical probability of a coin flip is always 50% heads, 50% tails

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Can someone help please ? Thanks I’m advance
Pani-rosa [81]

Answer:

f(-3) = 16

Step-by-step explanation:

Given:

f(x) = 2x² + x + 1

Required:

f(-3)

Solution:

Substitute x = -3 into f(x) = 2x² + x + 1

f(-3) = 2(-3)² + (-3) + 1

f(-3) = 2*9 - 3 + 1

f(-3) = 18 - 3 + 1

f(-3) = 16

6 0
3 years ago
What does 28+87÷3⋅2^3 equal
11111nata11111 [884]

Answer:

260

Step-by-step explanation:

28+29(23)

=28+(29)(8)

=28+232

7 0
3 years ago
Read 2 more answers
PLEASE ANSWER!!!!WILL MARK BRAINLIEST!!!
Setler79 [48]
Hope this is helpful

5 0
3 years ago
Q.6. The equation of the ellipse whose centre is at the origin and the x-axis, the major axis, which passes
azamat

<h3>Answer:</h3>

Equation of the ellipse = 3x² + 5y² = 32

<h3>Step-by-step explanation:</h3>

<h2>Given:</h2>

  • The centre of the ellipse is at the origin and the X axis is the major axis

  • It passes through the points (-3, 1) and (2, -2)

<h2>To Find:</h2>

  • The equation of the ellipse

<h2>Solution:</h2>

The equation of an ellipse is given by,

\sf \dfrac{x^2}{a^2} +\dfrac{y^2}{b^2} =1

Given that the ellipse passes through the point (-3, 1)

Hence,

\sf \dfrac{(-3)^2}{a^2} +\dfrac{1^2}{b^2} =1

Cross multiplying we get,

  • 9b² + a² = 1 ²× a²b²
  • a²b² = 9b² + a²

Multiply by 4 on both sides,

  • 4a²b² = 36b² + 4a²------(1)

Also by given the ellipse passes through the point (2, -2)

Substituting this,

\sf \dfrac{2^2}{a^2} +\dfrac{(-2)^2}{b^2} =1

Cross multiply,

  • 4b² + 4a² = 1 × a²b²
  • a²b² = 4b² + 4a²-------(2)

Subtracting equations 2 and 1,

  • 3a²b² = 32b²
  • 3a² = 32
  • a² = 32/3----(3)

Substituting in 2,

  • 32/3 × b² = 4b² + 4 × 32/3
  • 32/3 b² = 4b² + 128/3
  • 32/3 b² = (12b² + 128)/3
  • 32b² = 12b² + 128
  • 20b² = 128
  • b² = 128/20 = 32/5

Substituting the values in the equation for ellipse,

\sf \dfrac{x^2}{32/3} +\dfrac{y^2}{32/5} =1

\sf \dfrac{3x^2}{32} +\dfrac{5y^2}{32} =1

Multiplying whole equation by 32 we get,

3x² + 5y² = 32

<h3>Hence equation of the ellipse is 3x² + 5y² = 32</h3>
8 0
3 years ago
Which points are solutions to the system of inequalities shown below? Check all that apply.
Alexandra [31]
I: y<2*x
II: y<8
III: x>2

a: (5,3):
I: 3<2*5
3<10 ?yes
II: 3<8 ?yes
III: 5>2 ?yes
This is a solution

b: (6,0):
I: 0<2*6
0<12 ?yes
II: 0<8 ?yes
III: 6>2 ?yes
This is a solution

c: (3,3):
I: 3<2*3
3<6 ?yes
II: 3<8 ?yes
III: 3>2 ?yes
This is a solution

d: (1,-4):
I: -4<2*1
-4<2 ?yes
II: -4<8 ?yes
III: 1>2 ?no
This is not a solution

e: (4,-2):
I: -2<2*4
-2<8 ?yes
II: -2<8 ?yes
III: 4>2 ?yes
This is a solution

f: (5,9):
I: 9<2*5
9<10 ?yes
II: 9<8 ?no
This is not a solution

so a,b,c,e are solutions and d,f not
6 0
3 years ago
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