the amount is a positive "r", rate, thus is a growth equation, so it increased.
2.625e14. now all u have ro do is simplify it
Using the normal distribution relation, the probability that sample will exceed the weight limit is 0.004
<u>Using the relation</u> ::
The mean, μ = np = (162 × 19) = 3078
The standard deviation, σ = 28 × √19 = 122.049
<u>The Zscore</u> :
Zscore = (3401 - 3078) ÷ (122.049)
Zscore = 2.65
Hence,
P(Z > 2.65) = 1 - P(Z < 2.65)
Using a normal distribution table :
P(Z > 2.65) = 1 - 0.9959
P(Z > 2.65) = 0.004
Learn more : brainly.com/question/25204474
Answer:
s = sqrt [ Σ ( x i - x ) 2 / ( n - 1 ) ]
Step-by-step explanation:
where s is the sample standard deviation, x is the sample mean, x i is the ith element from the sample, and n is the number of elements in the sample. And finally, the standard deviation is equal to the square root of the variance.
F(x) = x²
g(x) = x - 3
g(-2) = (-2) - 3 = -5
f(-5) = (-5)² = 25
Answer : <span>(fog)(-2) = 25</span>
