Sorry I don't have enough time to deal with this problems, I believe that by using this formula you will easily come out with your answer. In the first one that has all sides you must use the law of cosines. Here is the formulas . Keep it because it is very helpful
Answer:
The answer is D.
Step-by-step explanation:
You have to make x as a subject by substracting 4 on both sides :
15 < 4 + x
15 - 4 < 4 + x - 4
11 < x
x > 11
1) in order to solve this problem you must to obtain The value of K, for it you know by definition that the horizontal slope of the side BC is zero ,
then m = Y2-Y/X2-X1, 0 = 5-K/4-6⇒0 = 5-K⇒K = 5
known this value for K you ca find the equation of thE line that pass through A and C
2) Following the same procedure in first place you calculate the slope with the points A(-2,1) Y C ( 4,5)
m= 5-1/4-(-2) = 2
now with any point A or C and the slope you obtain the line
A(-2,1)
y-y1 = m (x-x1) , Y-1= 2(X-(-2)⇒Y-1= 2X+4⇒Y=2X+4-1⇒Y =2X+3
6*-5= -30
x* x^4=x^5
Remember that since the base is the same, you multiply by adding the exponents, and 1+4=5.
Final answer: -30x^5
