1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
morpeh [17]
3 years ago
13

UMMMMMM HOWWW IS THIS POSSIBLEEEE https://brainly.com/question/1559324

Mathematics
2 answers:
Andre45 [30]3 years ago
7 0

Answer:

What?

Step-by-step explanation:

LiRa [457]3 years ago
6 0

Answer:

it says page not found

Step-by-step explanation:

You might be interested in
Graph the function. f(x)=|x+2|-1
timurjin [86]

Answer:

a v-shaped graph with a minimum at (-2,-1) and x-intercepts at -1 and -3

Step-by-step explanation:

if you need to graph the function then start by creating an x-y table of values:

when x=0, y=1

so you the point: (0, 1)

when x=2, y=3

you have another point: (2,3)

when x=-2, y = -1

third point: (-2,-1)

when x=-3, y = 0

fourth point: (-3,0)

7 0
2 years ago
Read 2 more answers
PLEASE HELP DUE IN 15 MINUTES!!
Lera25 [3.4K]

Answer:

<h2><u>Supplementary</u></h2><h2><u>x = 34</u></h2>

Explanation:

  • Supplementary angles: Angles that measure up to 180°
  • Write an equation to find x

4x + 10 + x = 180

  • Group like terms

4x + x + 10 = 180

  • Add: 4x + x = 5x

5x + 10 = 180

  • Subtract 10 from both sides

5x + 10 - 10 = 180 - 10

5x = 170

  • Divide both sides by 5

5x / 5 = 170 / 5

x = 34

6 0
3 years ago
Read 2 more answers
What situation should be used to rewrite 16(x^3+1)^2 -22(x^3+1)-3=0 as a quadratic equation
Oliga [24]
16(x^3+1)^2-22(x^3+1)-3=0

Use substitution:  x^3+1=t

16t^2-22t-3=0\\\\16t^2-24t+2t-3=0\\\\8t(2t-3)+1(2t-3)=0\\\\(2t-3)(8t+1)=0\iff2t-3=0\ \vee\ 8t+1=0

2t-3=0\ \ \ |+3\\\\2t=3\ \ \ |:2\\\\t=\dfrac{3}{2}\\..............................\\8t+1=0\ \ \ \ |-1\\\\8t=-1\ \ \ \ |:8\\\\t=-\dfrac{1}{8}

we're going back to substitution:

x^3+1=\dfrac{3}{2}\ \vee\ x^3+1=-\dfrac{1}{8}\ \ \ \ |subtract\ 1\ from\ both\ sides\ of\ the\ equations\\\\x^3=\dfrac{1}{2}\ \vee\ x^3=-\dfrac{9}{8}\\\\x=\sqrt[3]{\dfrac{1}{2}}\ \vee\ x=\sqrt[3]{-\dfrac{9}{8}}


x=\dfrac{1}{\sqrt[3]2}\ \vee\ x=-\dfrac{\sqrt[3]9}{2}\\\\\boxed{x=\dfrac{\sqrt[3]4}{2}\ \vee\ x=-\dfrac{\sqrt[3]9}{2}}

4 0
3 years ago
The perimeter is 528 inches if the width is 120 inches what is the length?
Sergeeva-Olga [200]

Answer: It is 144

Step-by-step explanation:

120+120 is 240 & 528-240 is 288

288 divided by 2 is 144

7 0
3 years ago
49 more than the quotient of an unknown number and 12 is 53. What is the value of the unknown number?
nalin [4]
The unknown number is 48 using the equation: x ÷ 12 +49=53 subtract 49 from both sides and get x ÷ 12 = 4 multiplying by 12 on both side to get rid of the ÷12 and get the final answer of x=48.
6 0
3 years ago
Other questions:
  • Use the base of the grassy area to find the approximate area of the circular garden use pi = 3.14 what’s the answer ?
    8·1 answer
  • Simplify the algebraic expression -2(x - 3) + 4(-2 x + 8) *
    6·2 answers
  • Express your answer as a polynomial in standard form.
    5·1 answer
  • , the vet told the Taylor's from problem 10 to disgrace the mount Molly eats by 3/4 cups after Molly's food is digested will she
    14·1 answer
  • Can someone check my math
    13·1 answer
  • Alex was planting a garden. he planted 2/5 of the garden with potatoes and 1/8 of the garden with lettuce. what fraction of the
    13·1 answer
  • Nate picked 5 2/3 pounds of berries. He divided them evenly among 3 containers. How many pounds of berries did Nate put in each
    7·1 answer
  • &lt;A and &lt;B are vertical angles. If m&lt;A = (7x - 8)⁰ and m&lt;B = (6x + 17)°, then find the value of x.​
    11·1 answer
  • An object containing the point (-6,10) was moved to the location (12,-2) . Which choice best described the translation?
    15·2 answers
  • Y = 3x + 4<br> What is the y-intercept?<br> What is the slope?
    12·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!