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Vladimir [108]
2 years ago
6

Read carefully and choose the name of the student who made the correct statement.

Mathematics
1 answer:
frosja888 [35]2 years ago
3 0

Answer: graph is 2/3

Step-by-step explanation: its up two and over 3 if you look at the graph you can see it hitting the graph :P hope this helps

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Does this set of ordered pairs represent a function? Why or why not. Don’t need a step to step just the answer
Scrat [10]

Answer:

D. Yes,because every x-value corresponds to exactly one y-value.

Step-by-step explanation:

The given ordered pairs are;

{(-5,-5),(-1,-2),(0,-2),(3,7),(8,9)}

We do not have the same x-value corresponding to more than one y-value.

We can see from the ordered pairs that every x-value corresponds to exactly one y-value.

Therefore the graph of this relation will pass the vertical line test.

3 0
3 years ago
Read 2 more answers
A regular hexagonal prism has an edge length 12 cm, and height 10 cm. Identify the volume of the prism to the nearest tenth.
Alexeev081 [22]

Check the picture below.

so the volume will simply be the area of the hexagonal face times the height.

\textit{area of a regular polygon}\\\\ A=\cfrac{1}{4}ns^2\stackrel{\qquad degrees}{\cot\left( \frac{180}{n} \right)}~~ \begin{cases} n=\stackrel{number~of}{sides}\\ s=\stackrel{length~of}{side}\\[-0.5em] \hrulefill\\ n=6\\ s=12 \end{cases}\implies A=\cfrac{1}{4}(6)(12)^2\cot\left( \frac{180}{6} \right) \\\\\\ A=216\cot(30^o)\implies A=216\sqrt{3} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{area of the hexagon}}{(216\sqrt{3})}~~\stackrel{height}{(10)}\implies 2160\sqrt{3}~~\approx ~~3741.2~cm^3

6 0
1 year ago
HELP PLEASE I HAVE A COUPLE MORE! Please help and fast would be great! BRAINLEST!!!
Harlamova29_29 [7]

Answer:

b. slope: -5; y-intercept: 7

Step-by-step explanation:

We are given the equation:

y + 5x = 7

To find the slope and y-intercept of the line, it would be helpful to get the equation into slope-intercept form. The slope-intercept form of a line is:

y = mx + b

where m is the slope and b is the y-intercept.

Lets get the given equation into slope-intercept form.

y + 5x = 7

Subtract 5x from both sides.

y = -5x + 7

Now we have the equation in slope-intercept form. By looking at the equation, we can see that the slope is -5 and that the y-intercept is 7.

The correct answer choice would be b.

I hope you find my answer and explanation to be helpful. Happy studying.

3 0
2 years ago
Use the Chain Rule (Calculus 2)
atroni [7]

1. By the chain rule,

\dfrac{\mathrm dz}{\mathrm dt}=\dfrac{\partial z}{\partial x}\dfrac{\mathrm dx}{\mathrm dt}+\dfrac{\partial z}{\partial y}\dfrac{\mathrm dy}{\mathrm dt}

I'm going to switch up the notation to save space, so for example, z_x is shorthand for \frac{\partial z}{\partial x}.

z_t=z_xx_t+z_yy_t

We have

x=e^{-t}\implies x_t=-e^{-t}

y=e^t\implies y_t=e^t

z=\tan(xy)\implies\begin{cases}z_x=y\sec^2(xy)=e^t\sec^2(1)\\z_y=x\sec^2(xy)=e^{-t}\sec^2(1)\end{cases}

\implies z_t=e^t\sec^2(1)(-e^{-t})+e^{-t}\sec^2(1)e^t=0

Similarly,

w_t=w_xx_t+w_yy_t+w_zz_t

where

x=\cosh^2t\implies x_t=2\cosh t\sinh t

y=\sinh^2t\implies y_t=2\cosh t\sinh t

z=t\implies z_t=1

To capture all the partial derivatives of w, compute its gradient:

\nabla w=\langle w_x,w_y,w_z\rangle=\dfrac{\langle1,-1,1\rangle}{\sqrt{1-(x-y+z)^2}}}=\dfrac{\langle1,-1,1\rangle}{\sqrt{-2t-t^2}}

\implies w_t=\dfrac1{\sqrt{-2t-t^2}}

2. The problem is asking for \frac{\partial z}{\partial x} and \frac{\partial z}{\partial y}. But z is already a function of x,y, so the chain rule isn't needed here. I suspect it's supposed to say "find \frac{\partial z}{\partial s} and \frac{\partial z}{\partial t}" instead.

If that's the case, then

z_s=z_xx_s+z_yy_s

z_t=z_xx_t+z_yy_t

as the hint suggests. We have

z=\sin x\cos y\implies\begin{cases}z_x=\cos x\cos y=\cos(s+t)\cos(s^2t)\\z_y=-\sin x\sin y=-\sin(s+t)\sin(s^2t)\end{cases}

x=s+t\implies x_s=x_t=1

y=s^2t\implies\begin{cases}y_s=2st\\y_t=s^2\end{cases}

Putting everything together, we get

z_s=\cos(s+t)\cos(s^2t)-2st\sin(s+t)\sin(s^2t)

z_t=\cos(s+t)\cos(s^2t)-s^2\sin(s+t)\sin(s^2t)

8 0
3 years ago
How to solve for this? Need help ASAP
garik1379 [7]

2ax-6ay+bx-3by

2ax+bx -6ay-3by

x(2a+b) -3y(2a+b)

(2a+b) (x-3y)

8 0
3 years ago
Read 2 more answers
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