ANSWER

EXPLANATION
We need to use the Pythagoras Theorem to find the height of the triangle.





Take positive square root to get;

Area =½bh


Step-by-step explanation:
the correct answer is :
C. y ≥ 2x-1
y ≤ ⅓x + 1
Answer:
The angle measure is 43 degrees
Step-by-step explanation:
The right angle adds up to 90 degrees in whole, you already have 47 degrees so you want to subtract 47 from 90, then you will get your answer.
Step-by-step explanation:
d/dx [f(x)]
= d/dx [(2x + 5)⁶]
= 6(2x + 5)⁵ * d/dx (2x + 5)
= 12(2x + 5)⁵.