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viktelen [127]
3 years ago
15

Please help me !!!!

Mathematics
2 answers:
nydimaria [60]3 years ago
5 0

Answer:

2(x+3)

Hope u get it correct!!!

Step-by-step explanation:

kompoz [17]3 years ago
5 0
I think the answer is 45 not sure tho
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In STU, the measure of
snow_lady [41]

Answer:

x=51.9

Step-by-step explanation:

sin x = 7.4/9.4

sin x= 0.787

sin^-1(0.787)=x

x=51.9

3 0
3 years ago
An airplane is traveling at an altitude of 30,000 feet
Mandarinka [93]

Answer:

Solution in photo

3 0
3 years ago
US<br> Find the value of x.<br> 80<br> 93<br> 112<br> y<br> Z<br> x = [?]
Elenna [48]

Answer:

x = 74°

Step-by-step explanation:

The diagram shown in this question, is a Quadrilateral inscribed in a circle

It is important to note that

The sum of opposite angles in a Quadrilateral = 180°

93° + z = 180°

z = 180° - 93°

z = 87°

In a cyclic quadrilateral,

Intercepted angle = 1/2(Intercepted arc)

Intercepted angle = 93°

Intercepted arc = x + 112°

Hence,

93° = 1/2(x + 112)°

93° × 2 = x + 112°

186° = x + 112°

x = 186° - 112°

x = 74°

6 0
4 years ago
You draw one card from a standard 52-card deck. Make a table to show the probability distribution for each sample space.{the car
Ivahew [28]

Answer:

Step-by-step explanation:

What is the probability that when two cards are drawn from a deck of cards without

replacement that both of them will be 8’s?

(ℎ 8

′

) = ( 8) ∙ ( 8)

( 8) =

4

52

 There are three 8’s left in the deck if one is pulled and not replaced, and 51 total

cards remaining.

( 8) =

3

51

(ℎ 8

′

) =

4

52 ∙

3

51 =

12

2652 =

1

221 = .0045 .45%

4 0
3 years ago
A fair coin is flipped twelve times. What is the probability of the coin landing tails up exactly nine times?
seraphim [82]

Answer:

P\left(E\right)=\frac{55}{1024}

Step-by-step explanation:

Given that a fair coin is flipped twelve times.

It means the number of possible sequences of heads and tails would be:

2¹² = 4096

We can determine the number of ways that such a sequence could contain exactly 9 tails is the number of ways of choosing 9 out of 12, using the formula

nCr=\frac{n!}{r!\left(n-r\right)!}

Plug in n = 12 and r = 9

       =\frac{12!}{9!\left(12-9\right)!}

       =\frac{12!}{9!\cdot \:3!}

       =\frac{12\cdot \:11\cdot \:10}{3!}            ∵ \frac{12!}{9!}=12\cdot \:11\cdot \:10

       =\frac{1320}{6}                   ∵ 3!\:=\:3\times 2\times 1=6

       =220

Thus, the probability will be:

P\left(E\right)=\frac{n\left(E\right)}{n\left(S\right)}

         =\frac{220}{4096}

         =\frac{55}{1024}

Thus, the probability of the coin landing tails up exactly nine times will be:

P\left(E\right)=\frac{55}{1024}

4 0
3 years ago
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