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Sophie [7]
3 years ago
6

When calculating compound interest, the periodic interest rate is always less than the annual interest rate. True or false

Mathematics
1 answer:
uranmaximum [27]3 years ago
6 0

Answer: False


Step-by-step explanation: If your Compounding interest, the periodic interest is Sometimes less than the annual interest because the period of interest could be say 2 years

Hope this helps ☺  


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Bx^(2)+2b^(2)-b^(3)-2x^(2)
8090 [49]

Answer:

(b+x)(−b+x)(b−2)

Step-by-step explanation:

Factor bx2 + 2b2 − b3 − 2x2  − b3 + bx2 + 2b2 − 2x2  = (b+x)(−b+x)(b−2)

hope this helps! :)

8 0
3 years ago
The attendance at twenty-five high school football games was: 250, 400, 350, 750, 200, 1000, 1200, 800, 600, 900,
wolverine [178]

Answer:

B and d

Step-by-step explanation:

Brainliest pls.

3 0
3 years ago
Find the principal which will yield simple interest of N55.60 for 1yr 6 months at the rate of 2%
Norma-Jean [14]

There should be a point the line is going through, (1,2).

We have given that,

N55.60 for 1yr 6 months at the rate of 2%

We have to determine the principal which will yield simple interest of N55.60 for 1yr 6 months at the rate of 2%.

<h3>What is the simple interest?</h3>

A = P (1 + rt)

A = final amount

P = initial principal balance

r = annual interest rate

t = time (in years)

x = inches

y = miles

per 1 inch = 2 miles

so on the graph, there should be a point the line is going through, (1,2).

To learn more about the simple interest visit:

brainly.com/question/2294792

#SPJ2

6 0
2 years ago
Use f(x) = 1/2 x and f -1(x) = 2x to solve the problems. f(2) = 1 f−1(1) = 2 f−1(f(2)) = 2 f−1(−2) = f(−4) = f(f−1(−2)) =
vampirchik [111]

Answer:

In this problem, we are given the following functions:

f(x)=\frac{1}{2}x

and its inverse function:

f^{-1}(x)=2x

First of all, we want to calculate f(2). This can be obtained by substituting

x = 2

into f(x). Doing so, we find:

f(2)=\frac{1}{2}\cdot 2 = 1

Then we want to calculate f^{-1}(1). We can do it by substituting

x = 1

into f^{-1}(x). Doing so,

f^{-1}(1)=2\cdot 1 = 2

Then we want to calculate f^{-1}(f(2)), which can be found by calculating f(2) and then using it as input for f^{-1}(x). We know that

f(2) = 1

Therefore,

f^{-1}(f(2))=f^{-1}(1)=2

Then we want to calculate f^{-1}(-2), which can be calculated by plugging

x = -2

into f^{-1}(x). Doing so,

f^{-1}(-2)=2\cdot (-2)=-4

Then we want to calculate f(-4); by substituting

x = 4

into f(x), we find

f(-4)=\frac{1}{2}\cdot (-4)=-2

Finally, we want to find f(f^{-1}(-2))

We know already that

f^{-1}(-2)=-4

So we have:

f(f^{-1}(-2))=f(-4)=-2

7 0
3 years ago
Read 2 more answers
Multiply or divide as indicated (a+b)^9 / (a+b)^4
Allushta [10]
I believe (a+b)^5 would be the answer
5 0
3 years ago
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