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drek231 [11]
3 years ago
7

Can Someone please help me !!! ( you have to fill out the blanks )

Mathematics
1 answer:
kondaur [170]3 years ago
8 0

Answer:

1. 5(a-6) = 5a-30

2. 2(3a-b) = 6a-2b

3. 5(-5x+3) = -25x+15

4. -(2c+3) = -2c-3

Both of their first step are correct (Show your calculations to explain)

x-9 = 5

x = 14

2x-18 = 10

2x = 28

x = 14

Step-by-step explanation:

All Above

You might be interested in
Suppose p" must approximate p with relative error at most 10-3 . Find the largest interval in which p* must lie for each value o
goblinko [34]

Answer:

[p-|p|*10^{-3} \, , \, p+|p|* 10^-3]

Step-by-step explanation

The relative error is the absolute error divided by the absolute value of p. for an approximation p*, the relative error is

r = |p*-p|/|p|

we want r to be at most 10⁻³, thus

|p*-p|/|p| ≤ 10⁻³

|p*-p| ≤ |p|* 10⁻³

therefore, p*-p should lie in the interval [ - |p| * 10⁻³ , |p| * 10⁻³ ], and as a consecuence, p* should be in the interval  [p - |p| * 10⁻³ , p + |p| * 10⁻³ ]

8 0
3 years ago
A company has 7 male and 9 female employees, and needs to nominate 2 men and 2 women for the company bowling team. How many diff
lys-0071 [83]

Answer:

The team can be formed in 756 different ways

Step-by-step explanation:

This is a combination problem since we are to select a set of people from a group. Combination has to do with selection.

for example, if r number of object is to be selected from a pool of n objects, this can be done in nCr number of ways.

nCr = \frac{n!}{(n-r)!r!}

Now If A company has 7 male and 9 female employees, and needs to nominate 2 men and 2 women for the company bowling team, then this can be done in the following way;

7C2 * 9C2

7C2 = \frac{7!}{5!2!} \\= \frac{7*6*5!}{5!*2} \\= 7*3\\= 21ways\\\\similarly;\\\\9C2 = \frac{9!}{7!2!}\\9C2= \frac{9*8*7!}{7!*2} \\9C2 = 9*4\\9C2 = 36

7C2 * 9C2 = 21*36

= 756

The team can be formed in 756 different ways

5 0
3 years ago
Travel A train makes a trip at 65 mi/h. A plane
Sladkaya [172]

Answer:

hihjjjkkcjkbcgukn c

Step-by-step explanation:

v mkkjljjj

8 0
2 years ago
Simplify: −6( 1 4 x - 2 3 x + 5 6 x)
Kisachek [45]

Answer:

= - 282x

Step-by-step explanation:

- 6(14x - 23x + 56x)

= - 84x + 138x - 336x

= 54x - 336x

= - 282x

3 0
3 years ago
Read 2 more answers
Will mark brainliest for the correct answer!
romanna [79]

Part (a)

Focus on triangle PSQ. We have

angle P = 52

side PQ = 6.8

side SQ = 5.4

Use of the law of sines to determine angle S

sin(S)/PQ = sin(P)/SQ

sin(S)/(6.8) = sin(52)/(5.4)

sin(S) = 6.8*sin(52)/(5.4)

sin(S) = 0.99230983787513

S = arcsin(0.99230983787513)

S = 82.889762826274

Which is approximate

------------

Use this to find angle Q. Again we're only focusing on triangle PSQ.

P+S+Q = 180

Q = 180-P-S

Q = 180-52-82.889762826274

Q = 45.110237173726

Which is also approximate.

A more specific name for this angle is angle PQS, which will be useful later in part (b).

------------

Now find the area of triangle PSQ

area of triangle = 0.5*(side1)*(side2)*sin(included angle)

area of triangle PSQ = 0.5*(PQ)*(SQ)*sin(angle Q)

area of triangle PSQ = 0.5*(6.8)*(5.4)*sin(45.110237173726)

area of triangle PSQ = 13.0074347717966

------------

Next we'll use the fact that RS:SP is 2:1.

This means RS is twice as long as SP. Consequently, this means the area of triangle RSQ is twice that of the area of triangle PSQ. It might help to rotate the diagram so that line PSR is horizontal and Q is above this horizontal line.

We found

area of triangle PSQ = 13.0074347717966

So,

area of triangle RSQ = 2*(area of triangle PSQ)

area of triangle RSQ = 2*13.0074347717966

area of triangle RSQ = 26.0148695435932

------------

We're onto the last step. Add up the smaller triangular areas we found

area of triangle PQR = (area of triangle PSQ)+(area of triangle RSQ)

area of triangle PQR = (13.0074347717966)+(26.0148695435932)

area of triangle PQR = 39.0223043153899

------------

<h3>Answer: 39.0223043153899</h3>

This value is approximate. Round however you need to.

===========================================

Part (b)

Focus on triangle PSQ. Let's find the length of PS.

We'll use the value of angle Q to determine this length.

We'll use the law of sines

sin(Q)/(PS) = sin(P)/(SQ)

sin(45.110237173726)/(PS) = sin(52)/(5.4)

5.4*sin(45.110237173726) = PS*sin(52)

PS = 5.4*sin(45.110237173726)/sin(52)

PS = 4.8549034284642

Because RS is twice as long as PS, we know that

RS = 2*PS = 2*4.8549034284642 = 9.7098068569284

So,

PR = RS+PS

PR = 9.7098068569284 + 4.8549034284642

PR = 14.5647102853927

-------------

Next we use the law of cosines to find RQ

Focus on triangle PQR

c^2 = a^2 + b^2 - 2ab*cos(C)

(RQ)^2 = (PR)^2 + (PQ)^2 - 2(PR)*(PQ)*cos(P)

(RQ)^2 = (14.5647102853927)^2 + (6.8)^2 - 2(14.5647102853927)*(6.8)*cos(52)

(RQ)^2 = 136.420523798282

RQ = sqrt(136.420523798282)

RQ = 11.6799196828694

--------------

We'll use the law of sines to find angle R of triangle PQR

sin(R)/PQ = sin(P)/RQ

sin(R)/6.8 = sin(52)/11.6799196828694

sin(R) = 6.8*sin(52)/11.6799196828694

sin(R) = 0.4587765387107

R = arcsin(0.4587765387107)

R = 27.3081879220073

--------------

This leads to

P+Q+R = 180

Q = 180-P-R

Q = 180-52-27.3081879220073

Q = 100.691812077992

This is the measure of angle PQR

subtract off angle PQS found back in part (a)

angle SQR = (anglePQR) - (anglePQS)

angle SQR = (100.691812077992) - (45.110237173726)

angle SQR = 55.581574904266

--------------

<h3>Answer: 55.581574904266</h3>

This value is approximate. Round however you need to.

8 0
3 years ago
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