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romanna [79]
3 years ago
15

1. For what equation is x = 5 a solution?

Mathematics
1 answer:
34kurt3 years ago
3 0
The answer is B. 3x= 15
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A trapezoid has an area of 20 cm2 and a height z cm. The lengths of the parallel sides are (2z + 3) cm and (6z – 1) cm. Find the
Brums [2.3K]

Answer: 2.11cm

Step-by-step explanation:

Given the following :

The lengths of the parallel sides are (2z + 3) cm and (6z – 1) cm

The area of trapezoid is calculated using the formula:

1/2(a + b) × h

Where ;

a = Length of side 1

b = length of side 2

h = height

Take a = (2z + 3) and b = (6z – 1), h = z

Therefore ;

1/2 (2z + 3 + 6z - 1) × z

Opening the bracket

(z + 1.5 + 3z - 0.5) × z

(4z + 1 ) × z = 20cm^2

4z^2 + z = 20cm^2

Using Quadratic formula:

4z^2 + z - 20 = 0

a = 4, b = 1, c = - 20

(-b±√b^2 -4ac) / 2a

Z = 2.11 or - 2.364

z cannot be negative, therefore,

Z = 2.11 cm

6 0
3 years ago
Help, don’t understand this problem.
Mila [183]

Answer:

(2, 3 )

Step-by-step explanation:

Given the 2 equations

3x - 5y = - 9 → (1)

x + 2y = 8 → (2)

Multiplying (2) by - 3 and adding to (1) will eliminate the x- term, that is

- 3x - 6y = - 24 → (3)

Add (1) and (3) term by term to eliminate x

(3x - 3x) + (- 5y - 6y) = (- 9 - 24), that is

- 11y = - 33 ( divide both sides by - 11 )

y = 3

Substitute y = 3 into either of the 2 equations and solve for x

Substituting in (2)

x + 2(3) = 8

x + 6 = 8 ( subtract 6 from both sides )

x = 2

Solution is (2, 3 )

8 0
3 years ago
Read 2 more answers
Given: m∠A = m∠C = 90°<br> AB ║ DC<br> Prove: ∆ABD ≅ ∆CDB<br> 40 points
leonid [27]

Answer:

ABD = CDB

AB is parallel to DC

Step-by-step explanation:

angle a and c are right angles so they are equal and angle b and d are equal because they have a line that touch both letters

AB and DC are parellel because they are the same looking lines just on oppisite sides

7 0
3 years ago
Who whats to talk <br> im here<br> .0.
Vsevolod [243]

Answer:

:( :( :(

Step-by-step explanation:

8 0
2 years ago
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write the equation of the parabola and a vertex form and standard form given the following information​
beks73 [17]

Answer:

see explanation

Step-by-step explanation:

The equation of a parabola in vertex form is

y = a(x - h)² + k

where (h, k) are the coordinates of the vertex and a is a multiplier

(9)

Here (h, k) = (3, - 2), thus

y = a(x - 3)² - 2

To find a substitute (2, 3) into the equation

3 = a(2 - 3)² - 2 ( add 2 to both sides )

5 = a(- 1)² = a , then

y = 5(x - 3)² - 2 ← in vertex form

y = 5(x² - 6x + 9) - 2

   = 5x² - 30x + 45 - 2

y = 5x² - 30x + 43 ← in standard form

(10)

Here (h, k) = (2, - 5), thus

y = a(x - 2)² - 5

To find a substitute (5, 4) into the equation

4 = a(5 - 2)² - 5 ( add 5 to both sides )

9 = a(- 3)² = 9a ( divide both sides by 9 )

a = 1

y = (x - 2)² - 5 ← in vertex form

y = x² - 4x + 4 - 5

y = x² - 4x - 1 ← in standard form

4 0
3 years ago
Read 2 more answers
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