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Goryan [66]
4 years ago
8

Danielle can run one mile is 8.835 minutes. Alex can run one mile is 9.75 minutes. How much

Mathematics
1 answer:
skad [1K]4 years ago
4 0

Answer:

Alex have to have 18.585 minutes to be running at the same amount of miles like daniella

Step-by-step explanation:

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26=8+v I dont know how to do this and I need help
Goshia [24]
26 = 8 + v equals v = 18.

First, 
subtract 8 from both sides. Your problem should look like 26 - 8 = v.
Second, simplify 26 - 8 to get 18. Your problem should look like 18 = v.
Third, switch sides. Your problem should look like v = 18, which is the correct answer.
3 0
3 years ago
The box plots show the summer temperatures, in degrees Fahrenheit, in two cities.
miskamm [114]

Answer:

The answer its C

Step-by-step explanation:

5 0
3 years ago
The owner of a ski resort estimates that a new 4-person ski lift will cost $5,500,000. The owner begins making payments on March
disa [49]

Amount must the owner make to have the cost of the ski lift in 5 years  is $6,711,045.22.

<h3>What is compound interest?</h3>

Compound interest is the addition of interest to the principal sum of a loan or deposit, or in other words, interest on principal plus interest.

A = P(1 + r/n)^{nt}

P =5,500,000

r =4%= 0.004

n =4

t= 5 years.

Now,

A = P(1 + r/n)^{nt}

A = 5,500,000.00(1 + 0.04/4)^{(4)(5)}

A = 5,500,000.00(1 + 0.01)^{20}

A = $6,711,045.22

Hence, The total amount accrued is $6,711,045.22.

Learn more about compound interest here:

brainly.com/question/14295570

#SPJ1

7 0
2 years ago
Question is show below.
WITCHER [35]

(1/4ab)^-2

Remove negative exponent by rewritten the equation as (4ab)^2

AUse Product rule to get:

4^2a^2b^2

Now raise 4 to the second power to get:

16a^2b^2


The last answer is correct.

7 0
3 years ago
Solve.<br>2x + 8y = 18<br>y= -x + 6<br>Enter your answer, in the form (x, y), in the boxes.​
iren2701 [21]

Answer:

it is a simultaneous equation and I used Elimination method

2x + 8y = 18(equ \: 1) \\   y =  - x + 6 \:  \\ y + x = 6 \: (equ \: 2) \\  \\ from \:( equ2) \\  \:  x = 6 - y \: (equ \: 3 )\\ sub. \: (equ3) \: in \: (equ2) \\ 2(6 - y )+ 8y = 18 \\ 12 - 2y + 8y = 18 \\ 6y = 18 - 12 \\ 6y = 6 \\  \frac{6y}{6}  =  \frac{6}{6}   \\  y = 1 \\  \\ sub. \: y \: in \: equ3 \\ x = 6 - y \\ x = 6 - 1 \\ x = 5 \\  \\  \\ y = 1 \:  \: x = 5

5 0
3 years ago
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