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2 years ago

Help is very much needed :)

Mathematics

1 answer:

ioda2 years ago

3 0

Answer:

Step-by-step explanation:

10/5 ×/3 multiply 10×3 and than divide by 5

or another way start with multiplying 5 and n equaling 5n=

than 10× 3= 30 so you're left with 5n=30 divied 30 by 5 equalling 6

so x=6

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-1/3+4+2/3 what is the answer plz and thank you

koban [17]

Hi there!

$- \frac{1}{3} + 4 + \frac{2}{3} =$
First we rearrange the sum in order to add both of the fractions first. We can rearrange because the only thing we need to do is adding.

$- \frac{1}{3} + \frac{2}{3} + 4 =$
Add the fractions.
** If you don't get this, think of this story: you lack 1/3 of an apple pie and someone gives you 2/3 of pie. How much pie do you have left?
- 1 / 3 + 2 / 3 = 1 / 3 **

$\frac{1}{3} + 4 =$
Finally add 4 to our found fraction.

$\boxed{ 4\frac{1}{3} }$
Therefore, the answer is 4 1/3.

5 0

3 years ago

Please show work for both problems

pentagon [3]

Answer:

1) x = 25 2) x = 23; m∠CBD = 80 degrees

Step-by-step explanation:

1) 5x + 15 = 6x - 10 Set both equations equal to each other

- 5x - 5x Subtract 5x from both sides

15 = x - 10

+ 10 + 10 Add 10 to both sides

25 = x

2) 2x + 14 + x + 7 = 90 Set the equations equal to 90

3x + 21 = 90 Combine like terms

- 21 - 21 Subtract 21 on both sides

3x = 69 Divide both sides by 3

x = 23

Plug 23 into the equation

2(23) + 14 = 60

5 0

3 years ago

Help me pls. Which expression shows the prime factorization of 48? 2 × 2 × 2 × 2 × 3 2 × 2 × 2 × 3 2 × 2 × 3 2 × 2 × 2 × 3 × 3

IceJOKER [234]

The first one which is 2 × 2 × 2 × 2 × 3

7 0

3 years ago

Read 2 more answers

What is the opposite of real number

Dafna1 [17]

An <em>imaginary number</em>. The defining property of an imaginary number is that has the number i attached to it, where i² = -1.

A few examples of imaginary numbers: 3i, i, -7i, (√3)i, (1/2)i

7 0

3 years ago

Read 2 more answers

It is believed that Lake Tahoe Community College (LTCC) Intermediate Algebra students get less than seven hours of sleep per nig

Kitty [74]

Answer: No , at 0.05 level of significance , we have sufficient evidence to reject the claim that LTCC Intermediate Algebra students get less than seven hours of sleep per night, on average.

Step-by-step explanation:

Let $\mu$ denotes the average hours of sleep per night.

As per given , we have

$H_0:\mu=7\\H_a:\mu$

, since $H_a$ is left-tailed and population standard deviation is unknown, so the test is a left-tailed t -test.

Also , it is given that ,

Sample size : n= 22

Sample mean : $\overline{x}=7.24$

Sample standard deviation : s= 1.93

Test statistic : $t=\dfrac{\overline{x}-\mu}{\dfrac{s}{\sqrt{n}}}$

i.e. $t=\dfrac{7.24-7}{\dfrac{1.93}{\sqrt{22}}}\approx0.58$

For significance level $\alpha=0.05$ and degree of freedom 21 (df=n-1),

Critical t-value for left-tailed test= $t_{\alpha, df}=t_{0.05,21}=- 1.7207$

Decision : Since the test statistic value (0.58) > critical value 1.7207, it means we are failed to reject the null hypothesis .

[Note : When $|t_{cal}|>|t_{cri}|$ , then we accept the null hypothesis.]

Conclusion: We have sufficient evidence to reject the claim that LTCC Intermediate Algebra students get less than seven hours of sleep per night, on average.

6 0

2 years ago