Answer:
cos(X+Y) = cos(55+35) = cos(90) = 0
Step-by-step explanation:
cos(X+Y) = cosXcosY - sinXsinY
cos(55+35) = cos(55)cos(35) - sin(55)sin(35)
cos(55+35) = cos(55)cos(35) - cos(90-55)cos(90-35)
cos(55+35) = cos(55)cos(35) - cos(35)cos(55)
cos(55+35) = 0
cos(90) = 0
Answer:
a=2.48
c=9.52
Step-by-step explanation:
a+c=12
4a+7.5c=72.5 Given
a+c=12
-4a-7.5c=-72.5 multiply the equation by negative 1
-3a-6.5c=-60.5 simplify
-3a=-60.5+6.5c add 6.5c to both sides
a=-20.17+2.17c divide it by 3
now you would take that equation and plug it into an equation you already have since you have something to plug in for a, the easiest one to do is a+c=12
(-20.17+2.17c)+c=12 plug in the equation
-20.17+3.17c=12 simplify by solving for c
3.17c=30.17 add 20.17 to both sides
c=9.52 divide both sides by 3.17
now since you have found c, you can plug it in to you equation to solve for a now (use the ones from the second step). I am using the equation a+c=12.
a+9.52=12 plug in the variable and solve for a
a=2.48 subtract 9.52 to both sides
a=2.48
c=9.52
Answer: 1957 meters
Solution: 4506-2549=1957
Therefore she ran 1957 meters more on Monday than on Tuesday.
Answer:
x = 10°
Step-by-step explanation:
a). Since, opposite angles of a cyclic quadrilateral are supplementary angles"
Therefore, in cyclic quadrilateral ABDE,
m∠ABD + m∠AED = 180°
110° + m∠AED = 180°
m∠AED = 180° - 110°
= 70°
b). AD = ED [Given]
m∠EAD = m∠AED [Since, opposite angles of equal sides are equal in measure]
m∠EAD = m∠AED = 70°
By triangle sum theorem in ΔABD,
m∠BAD + m∠ABD + m∠ADB = 180°
m∠BAD + 110° + 40° = 180°
m∠BAD = 180 - 150
= 30°
m∠AEB = m∠AED + m∠DAB [By angles addition postulate]
m∠AEB = 70° + 30°
= 100°
By triangle sum theorem in the large triangle,
x° + m∠AEB + m∠EAB = 180°
x° + 100° + 70° = 180°
x = 180 - 170
x = 10°
Answer:
20 5/8 yd^2
Step-by-step explanation:
width = 3 3/4 yd
length = 5 1/2 yd
First change both measurements to fractions.
3 3/4 = 3 + 3/4 = 12/4 + 3/4 = 15/4
5 1/2 = 5 + 1/2 = 10/2 + 1/2 = 11/2
area = length * width
area = 15/4 yd * 11/2 yd
area = (15 * 11)/(4 * 2) yd^2
area = 165/8 yd^2
165/8 = 20 remainder 5
area = 20 5/8 yd^2
