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Ber [7]
3 years ago
11

Please help asap im confused

Mathematics
1 answer:
scoray [572]3 years ago
3 0

Answer:

7

Step-by-step explanation:

im too smart sike

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A=6 cm,b=9cm,and c =3 cm
Crazy boy [7]
The lengths of sides a and c add to 9 cm, the length of side b.
In a triangle, the the sum of the lengths of any two sides must be greater than the the length of the third side. These dimensions do not make a triangle.

Is this really what you meant? Why did you use capital A for a side? Or is A an angle, and it measures 6 deg, not 6 cm?
4 0
3 years ago
Why cant i ask tutors for help??
Vilka [71]
Um probably bc ur not asking the correct ones?
7 0
3 years ago
Read 2 more answers
If IM is reflected across the x-axis and then translated along the vector <4, 1>, in
taurus [48]

Answer:

Final image L"M" will lie in the fourth quadrant.

Step-by-step explanation:

Coordinates of the ends of segment LM,

L  → (-3, 4)

M → (-3, 2)

Rule to reflect a point across x-axis is,

(x, y) → (x, -y)

By this rule, coordinates of the image point of L and M will be,

L(-3, 4) → L'(-3, -4)

M(-3, 2) → M'(-3, -2)

Further these image points are translated along the vector <4, 1>

Rule for this translation will be,

(x, y) → (x + 4, y + 1)

Now the image points of the points L' and M' will be,

L'(-3, -4) → L"(-3 + 4, -4 + 1)

             → L"(1, -3)

M'(-3, -2) → M"(-3 + 4, -2 + 1)

              → M"(1, -1)

Therefore, final image L"M" will lie in the fourth quadrant.

7 0
3 years ago
Need more points ??? solve this .....only first part for 50 points .....and follow me also!​
leonid [27]

Answer:

see below

Step-by-step explanation:

i.

= √(3 + 4i)

= 2 + i

ii.

= √(-8 + 6i)

= √2(-4 + 3i)

iii.

= √(-40 - 42i)

= √-2(20 + 21i)

iv.

= √i

= √i

v.

= \sqrt{\frac{2 + 3i}{5 - 4i} } +\sqrt{\frac{2-3i}{5+4i} }

= \sqrt{\frac{-2+23i}{41} } +\sqrt{\frac{2-3i}{46} }

7 0
3 years ago
Solve. Don't forget the $ sign! *
Leno4ka [110]

Answer:

$3, 661.60

Step-by-step explanation:

1703.44 + 1958.16

5 0
3 years ago
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