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Irina18 [472]
3 years ago
10

If f(x) = 3x – 2 and g(x) = 2x + 1, find (f – g)(x).

Mathematics
1 answer:
Andrej [43]3 years ago
8 0
3x-2-(2x+1)= 3x-2-2x-1
                  = x- 3
C. x - 3
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Use a related equation that has the variable on one side. Then simplify the other side.
dlinn [17]
I think that this equatios is than you need, x=t;

4 0
3 years ago
4x + y = 24 <br> 5x - y = 12<br> Applying systems of linear equations substitution, elimination.
Neko [114]
Using elimination you can eliminate 'y' to find x first.
4x=24
+ 5x=12
-------------
9x=36
9/9 x=36/9
X=4

Next use substitution to plug 4 back in to 'x'

4(4)+y=24
16+y=24
-16 -16
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Y=8
X is 4 and Y is 8
6 0
4 years ago
Simplify the square root of 5 times the cube root of 5.
mihalych1998 [28]

Answer:

Option 3 - five to the two thirds power

Step-by-step explanation:

Given : Expression 'the square root of 5 times the cube root of 5'.

To find : Simplify the expression ?

Solution :

Writing expression in numeric form,

The cube root of 5 means \sqrt[3]{5}

The square root of 5 times the cube root of 5 means \sqrt{5\sqrt[3]{5}}

Now, simplify the expression

\sqrt{5\sqrt[3]{5}}=\sqrt{5\times (5)^{\frac{1}{3}}}

\sqrt{5\sqrt[3]{5}}=\sqrt{(5)^{1+\frac{1}{3}}}

\sqrt{5\sqrt[3]{5}}=\sqrt{(5)^{\frac{4}{3}}}

\sqrt{5\sqrt[3]{5}}=((5)^{\frac{4}{3}})^{\frac{1}{2}}

\sqrt{5\sqrt[3]{5}}=(5)^{\frac{4}{3}\times \frac{1}{2}}

\sqrt{5\sqrt[3]{5}}=(5)^{\frac{2}{3}}

The expression is five to the two thirds power.

Therefore, Option 3 is correct.

3 0
3 years ago
Read 2 more answers
Type the correct answer in each box. Use numerals instead of words.
VARVARA [1.3K]

Answer:

see explanation

Step-by-step explanation:

f(x) = - (x + 1)(x - 3)(x + 2)

to find the zeros let f(x) = 0 , that is

- (x + 1)(x - 3)(x + 2) = 0

equate each factor to zero and solve for x

x + 1 = 0 ⇒ x = - 1

x - 3 = 0 ⇒ x = 3

x + 2 = 0 ⇒ x = - 2

the zeros are x = -1, 3 and x = - 2

to find the y- intercept let x = 0

f(0) = - (0 + 1)(0 - 3)(0 + 2) = - (1)(- 3)(2) = - (- 6) = 6

y- intercept is located at (0, 6 )

6 0
2 years ago
Factor completely. a^n+a^n+1
Naddika [18.5K]
The answer is 2a^n+1
5 0
3 years ago
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