I think that this equatios is than you need, x=t;
Using elimination you can eliminate 'y' to find x first.
4x=24
+ 5x=12
-------------
9x=36
9/9 x=36/9
X=4
Next use substitution to plug 4 back in to 'x'
4(4)+y=24
16+y=24
-16 -16
------------
Y=8
X is 4 and Y is 8
Answer:
Option 3 - five to the two thirds power
Step-by-step explanation:
Given : Expression 'the square root of 5 times the cube root of 5'.
To find : Simplify the expression ?
Solution :
Writing expression in numeric form,
The cube root of 5 means ![\sqrt[3]{5}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B5%7D)
The square root of 5 times the cube root of 5 means ![\sqrt{5\sqrt[3]{5}}](https://tex.z-dn.net/?f=%5Csqrt%7B5%5Csqrt%5B3%5D%7B5%7D%7D)
Now, simplify the expression
![\sqrt{5\sqrt[3]{5}}=\sqrt{5\times (5)^{\frac{1}{3}}}](https://tex.z-dn.net/?f=%5Csqrt%7B5%5Csqrt%5B3%5D%7B5%7D%7D%3D%5Csqrt%7B5%5Ctimes%20%285%29%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D%7D)
![\sqrt{5\sqrt[3]{5}}=\sqrt{(5)^{1+\frac{1}{3}}}](https://tex.z-dn.net/?f=%5Csqrt%7B5%5Csqrt%5B3%5D%7B5%7D%7D%3D%5Csqrt%7B%285%29%5E%7B1%2B%5Cfrac%7B1%7D%7B3%7D%7D%7D)
![\sqrt{5\sqrt[3]{5}}=\sqrt{(5)^{\frac{4}{3}}}](https://tex.z-dn.net/?f=%5Csqrt%7B5%5Csqrt%5B3%5D%7B5%7D%7D%3D%5Csqrt%7B%285%29%5E%7B%5Cfrac%7B4%7D%7B3%7D%7D%7D)
![\sqrt{5\sqrt[3]{5}}=((5)^{\frac{4}{3}})^{\frac{1}{2}}](https://tex.z-dn.net/?f=%5Csqrt%7B5%5Csqrt%5B3%5D%7B5%7D%7D%3D%28%285%29%5E%7B%5Cfrac%7B4%7D%7B3%7D%7D%29%5E%7B%5Cfrac%7B1%7D%7B2%7D%7D)
![\sqrt{5\sqrt[3]{5}}=(5)^{\frac{4}{3}\times \frac{1}{2}}](https://tex.z-dn.net/?f=%5Csqrt%7B5%5Csqrt%5B3%5D%7B5%7D%7D%3D%285%29%5E%7B%5Cfrac%7B4%7D%7B3%7D%5Ctimes%20%5Cfrac%7B1%7D%7B2%7D%7D)
![\sqrt{5\sqrt[3]{5}}=(5)^{\frac{2}{3}}](https://tex.z-dn.net/?f=%5Csqrt%7B5%5Csqrt%5B3%5D%7B5%7D%7D%3D%285%29%5E%7B%5Cfrac%7B2%7D%7B3%7D%7D)
The expression is five to the two thirds power.
Therefore, Option 3 is correct.
Answer:
see explanation
Step-by-step explanation:
f(x) = - (x + 1)(x - 3)(x + 2)
to find the zeros let f(x) = 0 , that is
- (x + 1)(x - 3)(x + 2) = 0
equate each factor to zero and solve for x
x + 1 = 0 ⇒ x = - 1
x - 3 = 0 ⇒ x = 3
x + 2 = 0 ⇒ x = - 2
the zeros are x = -1, 3 and x = - 2
to find the y- intercept let x = 0
f(0) = - (0 + 1)(0 - 3)(0 + 2) = - (1)(- 3)(2) = - (- 6) = 6
y- intercept is located at (0, 6 )