Answer:
55
Step-by-step explanation:
Add 15+5+25+10 which is 55
hope this helps! :)
The square root of 5,000 is 70.7106781187.
<h2>
Answer:<u>
158.7 is the answer</u></h2><h2><u>or it can be</u>
<u>89.7</u></h2>
Step-by-step explanation:
<h2>
<u>69 + Percentage increase =
</u></h2><h2>
<u>69 + (130% × 69) =
</u></h2><h2>
<u>69 + 130% × 69 =
</u></h2><h2>
<u>(1 + 130%) × 69 =
</u></h2><h2>
<u>(100% + 130%) × 69 =
</u></h2><h2>
<u>230% × 69 =
</u></h2><h2>
<u>230 ÷ 100 × 69 =
</u></h2><h2>
<u>230 × 69 ÷ 100 =
</u></h2><h2>
<u>15,870 ÷ 100 =
</u></h2><h2>
<u>158.7</u></h2><h2>
<u /></h2><h2>
<u /></h2><h2>
<u>69 increased by 130% = 158.7
</u></h2><h2>
<u>Absolute change (actual difference):
</u></h2><h2>
<u>158.7 - 69 = 89.7</u></h2>
What we know:
Mrs Lemke has a total of 10 2/3 oz of fertilizer
3/4 oz fertilizer per plant
What we need to find is left over fertilizer after equally distributing as much 3/4 oz of fertilizer per plant.
10 2/3 oz must be divided into groups of 3/4 oz
Those groups will show how many plants can be fertilized with each receiving 3/4 oz of fertilizer and the remainder will be the left over fertilizer in ounces we need to find.
First we must change 10 2/3 into an improper fraction of 32/3.
Now, we divide 32/3 by 3/4.
(32/3)/(3/4)=(32/3)x(4/3)
(32x4)/(3x3)=128/9
128/9 equals to 14 with a remainder of 2/9
That means Mrs Lemke can fertilize 14 plants with 3/4 oz of fertilizer each and have left over of 2/9 ounces.
Your answer is the remainder which is 2/9 ounces.
Answer:
B) Mean
Step-by-step explanation:
Standard Deviation is the measure of the amount of variation or dispersion of a set of values. Standard Deviation is represented by lower case Greek alphabet sigma σ. Standard Deviation is the square root of variance. Variance is the average of the squared differences or variation or dispersion from the Mean. Therefore, to compute standard deviation, the mean of the given data must be known.
Standard Deviation, σ = 
σ = 
∑
where
are the values of the sample observed,
X is the mean value of these observations, and
N is the number of observations in the sample.
