The result of our calculations about the rate and time are:
<h3>What is rate?</h3>
Rate can be regarded as the given object with respect to time.
falcon flies= 800,000 meters
t= 4 hours
We were given the formula as (d = rt)
d= distance
r = rate
t = time
We can make our calculations as:
part a:
r=d/t
part b:
falcon's rate in meters per hour = 800,000 meters / 4 hours = 200000m/hr
part c:
falcon's rate in kilometers per hour=(200000m/hr *(1/1000)=200km/hr
part d:
km/hr
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Answer:
68 degree
Step-by-step explanation:
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Answer:
B (300, 400)
Step-by-step explanation:
The profit maximization will be when the sum of the products will be greater. The maximum profit will be when x is 300 and y is 400. If we put in the equation :
P = 40x + 55 y
A - When x = 0 , y = 500
P = [40 * 0] + [55 * 500]
P = 27500
B -
When x = 300 , y = 400
P = [40 * 300] + [55 * 400]
P = 34000
C -
When x = 380 , y = 200
P = [40 * 380] + [55 * 200]
P = 26200
D -
When x = 400 , y = 0
P = [40 * 400] + [55 * 400]
P = 16000
Answer:
x = 1, y = 2, z = -1
Step-by-step explanation:
2x + 4y = 10
2x = -4y + 10
x = -2y + 5
now sub -2y + 5 in for x, back into the other 2 equations
2x + 2y + 3z = 3 -3x + y + 2z = -3
2(-2y + 5) + 2y + 3z = 3 -3(-2y + 5) + y + 2z = -3
-4y + 10 + 2y + 3z = 3 6y - 15 + y + 2z = -3
-2y + 3z = 3 - 10 7y + 2z = - 3 + 15
-2y + 3z = - 7 7y + 2z = 12
-2y + 3z = -7....multiply by 2
7y + 2z = 12...multiply by -3
--------------------------
-4y + 6z = -14 (result of multiplying by 2)
-21y - 6z = -36 (result of multiplying by -3)
---------------------------add
-25y = - 50
y = -50/-25
y = 2 <===
2x + 4y = 10 2x + 2y + 3z = 3
2x + 4(2) = 10 2(1) + 2(2) + 3z = 3
2x + 8 = 10 2 + 4 + 3z = 3
2x = 10 - 8 6 + 3z = 3
2x = 2 3z = 3 - 6
x = 2/2 3z = -3
x = 1 <== z = -3/3
z = -1 <===