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2 years ago

Who knows how to do this I TRULY NEED HELP

Mathematics

2 answers:

wariber [46]2 years ago

8 0

Answer:

Yes

Step-by-step explanation:

two of the different sides match

andrey2020 [161]2 years ago

4 0

When I’m doubt C it out

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Rewrite the decimal as the front as a fraction in simplest form 0.27

torisob [31]

So .27 means .27/1 or 2.7/10 or 27/100 or 270/1000 and so on

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3 years ago

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Solve for “a” 11a + 5 = -6

Shalnov [3]

Answer:

a=-1

Step-by-step explanation:

-6-5=-11

-11/11=-1

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3 years ago

Answer all questions shown

FromTheMoon [43]

SOH CAH TOA

—>

Sin D = 13 sqrt3/26 = 0.76
Sin E = 13/26 = 0.47
Cos D = 13/26 = 0.87
Cos E = 13 sqrt3/26 = 0.64

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2 years ago

Help me please!!! ..

12345 [234]

Step-by-step explanation:

HERE,

as,it is a right angle triangle,

x= $\tt{\sqrt{8^2+6^2} }$

$\tt{ x=\sqrt{64+36} }$

$\tt{ x=\sqrt{100} }$

$\tt{x=10km. }$

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2 years ago

Given cscx/cotx=sqrt2, find a numerical value of one trigonometric function of x.

Firlakuza [10]

$\frac{csc (x)}{cot (x)} = \sqrt{2}$

⇒ $\frac{csc (x)}{1} * \frac{1}{cot (x)} = \sqrt{2}$

⇒ $\frac{1}{sin (x)} * \frac{sin(x)}{cos (x)} = \sqrt{2}$

⇒ $\frac{1}{cos (x)} = \sqrt{2}$ ; sin(x) ≠ 0, cos(x) ≠ 0

⇒ $\frac{cos (x)}{1} = \frac{1}{\sqrt{2}}$ ; sin(x) ≠ 0, cos(x) ≠ 0

⇒ $cos (x) = \frac{\sqrt{2}}{2}$

Use the Unit Circle to determine when $cos (x) = \frac{\sqrt{2}}{2}$

Answer: 45° and 315° $(\frac{\pi}{4} and \frac{7\pi }{4} )$

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2 years ago

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