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OleMash [197]
4 years ago
7

Two cyclists, 112 miles apart, start riding toward each other at the same time. One cycles 3 times as fast as the other, and the

y meet after 4 hours of riding.
a. Write an equation using the information as it is given above that can be solved to answer this problem. Use the variable r to represent the speed of the slower cyclist.

b. What are the speeds of the two cyclists? Put both values in the answerbox, separated with a comma, and select the appropriate units.
Mathematics
1 answer:
Iteru [2.4K]4 years ago
5 0

Answer:

Speed of a= 21 miles/hr

r = Speed of b= 7 miles/hr

Speed of a = 3r

Step-by-step explanation:

The cyclist are 112 miles apart

Time traveled by two = 4 hours

Speed of a = 3 * speed of b

If a cylcles 3 times More than b, then a will cover 3*distance of b

But speed = distance/time

Time = 4hours

Total distance=112

a = 3b

3b + b = 112

4b = 112

b = 112/4

b = 28 miles

a = 3b

a = 3*28

a = 84 Miles

They bought traveled 4 hours

Speed of a = 84miles/4 hours

Speed of a= 21 miles/hr

Speed of b = 28miles/4 hours

Speed of b = 7 miles/hr

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For the figures below, assume they are made of semicircles, quarter circles and squares. For each shape, find the area and perim
ICE Princess25 [194]

Answer:

Part a) The area of the figure is \frac{9}{2}(4+\pi )\ cm^{2}

Part b) The perimeter of the figure is 3(2+2\sqrt{2}+ \pi)\ cm

Step-by-step explanation:

Step 1

Find the area of the figure

In this problem we have that

The figure ABC is the half of a square and the other figure is a semicircle

<u>Find the area of the figure ABC</u>

we have

AB=6\ cm, BC=6\ cm

The area of the half square ABC is equal to find the area of triangle ABC

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The area of the semicircle is equal to

A2=\pi r^{2}/2

we have that

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substitute

A2=\pi (3)^{2}/2

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The area of the figure is equal to

18\ cm^{2}+(9/2) \pi\ cm^{2}= \frac{9}{2}(4+\pi )\ cm^{2}

Step 2

Find the perimeter of the figure

The perimeter of the figure is equal to

P=AB+AC+length\ CB

we have

AB=6\ cm

Applying Pythagoras theorem

AC=\sqrt{6^{2}+6^{2}}\\AC=6\sqrt{2}\ cm

Remember that

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C=\frac{1}{2}2\pi r=\pi r

r=6/2=3\ cm

C=\pi(3)

C=3 \pi\ cm

The perimeter of the figure is equal to

P=6\ cm+6\sqrt{2}\ cm+3 \pi\ cm

Simplify

P=3(2+2\sqrt{2}+ \pi)\ cm

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