A triangle has sides with lengths of 12 kilometers, 16 kilometers, and 20 kilometers.

What is the volume of the right rectangular prism?

ddd [48]

Answer:

i think its 735

Step-by-step explanation:

since the base is a square it should be a whole square which is 7 and the height is 15 and v=whl and multiply all of it 7 times 7 is 49 times 15 is 735.

5 0

3 years ago

A 30-foot pole is stabilized by a wire attached to the ground 10 feet from the base of the pole. how long is the wire?

Leya [2.2K]

Answer:

height of the pole is 16.1

6 0

3 years ago

On a linear X temperature scale, water freezes at −115.0°X and boils at 325.0°X. On a linear Y temperature scale, water freezes

belka [17]

Answer:

The current temperature on the X scale is 1150 °X.

Step-by-step explanation:

Let is determine first the ratio of change in X linear temperature scale to change in Y linear temperature scale:

$r = \frac{\Delta T_{X}}{\Delta T_{Y}}$

$r = \frac{325\,^{\circ}X-(-115\,^{\circ}X)}{-25\,^{\circ}Y - (-65.00\,^{\circ}Y)}$

$r = 11\,\frac{^{\circ}X}{^{\circ}Y}$

The difference between current temperature in Y linear scale with respect to freezing point is:

$\Delta T_{Y} = 50\,^{\circ}Y - (-65\,^{\circ}Y)$

$\Delta T_{Y} = 115\,^{\circ}Y$

The change in X linear scale is:

$\Delta T_{X} = r\cdot \Delta T_{Y}$

$\Delta T_{X} = \left(11\,\frac{^{\circ}X}{^{\circ}Y} \right)\cdot (115\,^{\circ}Y)$

$\Delta T_{X} = 1265\,^{\circ}X$

Lastly, the current temperature on the X scale is:

$T_{X} = -115\,^{\circ}X + 1265\,^{\circ}X$

$T_{X} = 1150\,^{\circ}X$

The current temperature on the X scale is 1150 °X.

5 0

3 years ago

Which system of linear inequalities is represented by the graph?

Nikitich [7]

Answer:

C.

Step-by-step explanation:

Easiest and fastest way to determine your answer is to graph the systems of inequalities on a graphing calc. Once you do so, you should be able to see that Choice C is the correct answer.

6 0

3 years ago

Follow the process of completing the square to solve 2x2 + 8x - 12 = 0.

Rom4ik [11]

Please: Use "^" to denote exponentiation: 2x^2 + 8x - 12 = 0

Reduce this by div. every term by 2: x^2 + 4x - 6 = 0

Here a=1, b=4 and c = -6. Square half of b, obtaining (4/2)^2 = 4, and add, and then subtract, this 4 to x^2 + 4x - 6:

 x^2 + 4x +4 - 4 - 6 = 0. Rewrite the square as (x+2)^2, obtaining new equation

(x+2)^2 = 10. Take the sqrt of both sides: x+2 = plus or minus sqrt(10).

Finally, solve for x: x = -2 plus or minus sqrt(10).

8 0

3 years ago