Which better describes the data set, the mean or the median?

Mathematics

2 answers:

Xelga [282]2 years ago

8 0

The median...(hope it helps)

Serga [27]2 years ago

3 0

You would need to give us the data set to answer this question. I'm assuming this is a stats question which means I'd need to see what set of data you are working with to determine if the mean or median is best to describe the center. The meadian is resistant to outlying values while the mean is not. Therefore the meadian is a better describer for skewed distributions. Whenever you have outliers the dataset is skewed. Take a look at the shape of the data. Does it look skewed? You can make a simple graph with the data points to determine if there are outliars if you aren't able to tell just from looking at the data. (Again I don't know what data you are working with, but I hope this helped)

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If sec= 5/3 and the terminal point determined by is in quadrant 4, then

OLga [1]

$\bf sec(\theta)=\cfrac{1}{cos(\theta)}\\\\
-----------------------------\\\\
sec(\theta)=\cfrac{5}{3}\implies \cfrac{1}{cos(\theta)}=\cfrac{5}{3}\implies \cfrac{3}{5}=cos(\theta)
\\\\\\
\textit{now, }\theta\textit{ is in the 4th quadrant}$

so... notice the picture below, the angle in the fourth quadrant
now... notice, the cosine is just the distance the angle makes with the x-axis
so... using the pythagorean theorem, get the opposite side, from that triangle, keeping in mind that, "y" is negative in the 4th quadrant

once you get "y", get any other trigonometry value you need :)