The number of tests that it would take for the probability of committing at least one type I error to be at least 0.7 is 118 .
In the question ,
it is given that ,
the probability of committing at least , type I error is = 0.7
we have to find the number of tests ,
let the number of test be n ,
the above mentioned situation can be written as
1 - P(no type I error is committed) ≥ P(at least type I error is committed)
which is written as ,
1 - (1 - 0.01)ⁿ ≥ 0.7
-(0.99)ⁿ ≥ 0.7 - 1
(0.99)ⁿ ≤ 0.3
On further simplification ,
we get ,
n ≈ 118 .
Therefore , the number of tests are 118 .
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Take DEBC a parralelogram
Parralel sides are DE and BC
THEREFORE,
1/2*(a+b)*h
1/2*(6+15)*h
1/2*(21)*h=0
10.5*h=0
h=-10.5
Hello Anna,
(a)
1.25 per ticket
? number of rides (x)
43.75 total cost (y)
Admission (z)
(b) Linear Equation - 1.25x + z = y
(c) Well you need to calculate the totaly number of rides that person took and add that to the admission cost.
Answer:
x = 9.5 m
Step-by-step explanation:
Given:
This problem is based on 2D motion kinematics equations:
At maximum height:
Components of initial velocity:
To find time to reach maximum height:
Plugging in the known values:
0 = 4.10 - 9.8t
Total time = 2t = 2(0.418) = 0.836 s
to find horizontal distance covered:
The value of x is 4
so it says that 3 times __ equals 12.
so that means that u have to do 12/3 Wi-Fi i equals 4, so that is how u do it
hope this helps!!
