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3 years ago

10

It takes four hours to mow two

2 answers:

natulia [17]3 years ago

8 0

He will be able to mow 5 lawns.

iragen [17]3 years ago

7 0

Answer:

5

Step-by-step explanation:

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The figure shows ∆ABC with m∠ABC = 90°.

notsponge [240]

Answer:

Hello,

Please, see the attached file.

Thanks.

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

g A milling process has an upper specification of 1.68 millimeters and a lower specification of 1.52 millimeters. A sample of pa

adoni [48]

Complete Question

A milling process has an upper specification of 1.68 millimeters and a lower specification of 1.52 millimeters. A sample of parts had a mean of 1.6 millimeters with a standard deviation of 0.03 millimeters. what standard deviation will be needed to achieve a process capability index f 2.0?

Answer:

The value required is $\sigma = 0.0133$

Step-by-step explanation:

From the question we are told that

The upper specification is $USL = 1.68 \ mm$

The lower specification is $LSL = 1.52 \ mm$

The sample mean is $\mu = 1.6 \ mm$

The standard deviation is $\sigma = 0.03 \ mm$

Generally the capability index in mathematically represented as

$Cpk = min[ \frac{USL - \mu }{ 3 * \sigma } , \frac{\mu - LSL }{ 3 * \sigma } ]$

Now what min means is that the value of CPk is the minimum between the value is the bracket

substituting value given in the question

$Cpk = min[ \frac{1.68 - 1.6 }{ 3 * 0.03 } , \frac{1.60 - 1.52 }{ 3 * 0.03} ]$

=> $Cpk = min[ 0.88 , 0.88 ]$

So

$Cpk = 0.88$

Now from the question we are asked to evaluated the value of standard deviation that will produce a capability index of 2

Now let assuming that

$\frac{\mu - LSL }{ 3 * \sigma } = 2$

So

$\frac{ 1.60 - 1.52 }{ 3 * \sigma } = 2$

=> $0.08 = 6 \sigma$

=> $\sigma = 0.0133$

So

$\frac{ 1.68 - 1.60 }{ 3 * 0.0133 }$

=> $2$

Hence

$Cpk = min[ 2, 2 ]$

So

$Cpk = 2$

So $\sigma = 0.0133$ is the value of standard deviation required

3 0

3 years ago

a plumber charges $55 for a service call plus $35 per hour. if the plumber’s bill was $160, how many hours was he there?

Allushta [10]

He was there for 3 hours cause 3 x 35 = 105 but 105 + 55 = 160

5 0

3 years ago

Read 2 more answers

Will u help me?

sergey [27]

Answer:

Charles practiced for the relay race for D. 9 hours last week.

Step-by-step explanation:

First, I would find the ratios the ratios for converting hurdle to javelin and javelin to relay.

Hurdle : Javelin ; 5 : 1.5

Javelin : Relay ; 2.5 : 5 or 1 : 2

Next, find the factors compared to the original numbers for hurdle to javelin.

15 / 5 = 3

To find the amount of javelin time they did, multiply 1.5 by the factor we got, 3.

1.5 * 3 = 4.5

Finally, double 4.5, since Charles does twice as much relay than he does javelin.

4.5 * 2 = 9 hours

3 0

3 years ago

13) Based on her results, what is the experimental probability of landing on a blue section?

AveGali [126]

I believe that it would be a-21/49

6 0

3 years ago