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QveST [7]
2 years ago
5

The height, h, in feet of a piece of cloth tied to a waterwheel in relation to sea level as a function of time, t, in seconds ca

n be modeled by the equation h = 15 cosine (StartFraction pi Over 20 EndFraction t). How long does it take for the waterwheel to complete one turn?
5 seconds
10 seconds
20 seconds
40 seconds
Mathematics
1 answer:
Anni [7]2 years ago
7 0

Considering the period of the cosine function, it is found that it takes 40 seconds for the wheel to complete one turn.

<h3>What is the period of the cosine function?</h3>

The cosine function is defined by:

f(x) = acos(bx + c) + d.

For the period, we have to look at coefficient b, and the period is:

P = 2π/|B|

For this problem, the function is given by:

h(x) = 15 cos(π/20)

Hence B = π/20, and the period is:

P = 2π/|B| = 2π/(π/20) = 2 x 20 = 40 seconds.

Hence it takes 40 seconds for the wheel to complete one turn.

More can be learned about the period of trigonometric functions at brainly.com/question/12502943

#SPJ1

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Unit 4 Test, Part 2: Congruence and Constructions<br> Help with my math please
lakkis [162]

Answer/Step-by-sep explanation:

1. Given:

∆NMK ≅ ∆TRP

\overline{NM} = 20

\overline{MK} = 15

\overline{KN} = 25

\overline{TR} = 3x - 1

a. To complete the congruent statement, thus: ∆MNK ≅ ∆RTP

b. The side that is congruent to \overline{TR} is \overline{NM}. Thus:

\overline{TR} ≅ \overline{NM}

c. Since \overline{TR} ≅ \overline{NM}, therefore:

\overline{TR} = \overline{NM}

3x - 1 = 20 (substitution)

Add 1 to both sides

3x = 20 + 1

3x = 21

Divide both sides by 3

x = \frac{21}{3}

x = 7

2. a. Slope of LK = \frac{rise}{run} = \frac{4}{3}

Slope of LM = \frac{rise}{run} = -\frac{3}{5}

b. ✍️Length of LK is the distance between L(-7, 4) and (-4, 8):

Lk = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

Lk = \sqrt{(-4 -(-7))^2 + (8 - 4)^2}

Lk = \sqrt{(3)^2 + (4)^2}

Lk = \sqrt{9 + 16}

Lk = \sqrt{25}

Lk = 5

✍️Length of LM is the distance between L(-7, 4) and (-2, 1):

LM = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

LM = \sqrt{(-2 -(-7))^2 + (1 - 4)^2}

LM = \sqrt{(5)^2 + (-3)^2}

LM = \sqrt{25 + 9}

LM = \sqrt{34}

LM = 5.8 (nearest tenth)

∆KLM is not an isosceles ∆ because it does not has two equal side lengths. This we can see because LK and LM are not equal.

Therefore, Anthony is incorrect. Am isosceles ∆ has two equal sides.

8 0
3 years ago
Multiplicative inverse thx!
wel
The multiplicative inverse of -1/3 is -3.
8 0
3 years ago
What is the first step in solving the quadratic equation x2 = StartFraction 9 Over 16 EndFraction? Take the square root of both
balu736 [363]

Answer:

The first step is

Take the square root of both sides of the equation

Step-by-step explanation:

we have

x^{2} =\frac{9}{16}

Solve for x

step 1

Take square root both sides

x=(+/-)\frac{3}{4}

the solutions are

x=+\frac{3}{4} and  x=-\frac{3}{4}

therefore

The first step is

Take the square root of both sides of the equation

5 0
3 years ago
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If kdkdkdkdkbenennsj
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3 years ago
3.5,-2,0,-7/3,-6 in order from greatest to least
icang [17]

Answer:

in order from greatest to least:

3.5  0  -2  -7/3  -6

Step-by-step explanation:

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