Answer: 
Step-by-step explanation:
Given: u and v be are the solutions of
Let
is the quadratic equation and u and v are the zeroes/solutions then
Sum of zeroes; 
Product of zeroes; 
Comparing
to
we get a= 3 , b= 5 and c = 7


Now we have to find
adding and subtracting 2uv in numerator we get

Substituting the values from (i) and (ii) we get

Hence, the value of
is 
Answer:
6x + 1
Step-by-step explanation:
Distribute
3 + 2 ( x- 1 ) + 4x
3 + 2x - 2 + 4x
Subtract
3 + 2x - 2 + 4x
1 + 2x + 4x
Like terms
1 + 2x + 4x
1 + 6x
Rearrange
6x + 1
So because the discriminant is less than zero so this mean that the quadratic has no real solutions
Answer:
51
Step-by-step explanation:
The answer would be 51 because the numbers behind the decimal are below 5