The equations to calculate the legs are 0.5(x)(x + 2) = 24, x^2 + 2x - 48 = 0 and x^2 + (x + 2)^2 = 100
<h3>How to determine the legs of the triangle?</h3>
The complete question is in the attached image
The given parameters are:
Area = 24
Legs = x and x + 2
The area of the triangle is calculated as:
Area = 0.5 * Base * Height
This gives
0.5 * x * (x + 2) = 24
So, we have:
0.5(x)(x + 2) = 24
Divide through by 0.5
(x)(x + 2) = 48
Expand
x^2 + 2x = 48
Subtract 48 from both side
x^2 + 2x - 48 = 0
Hence, the equations to calculate the legs are 0.5(x)(x + 2) = 24, x^2 + 2x - 48 = 0 and x^2 + (x + 2)^2 = 100
Read more about area at:
brainly.com/question/24487155
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Numbers expressed using exponents are called base :)
D. 4.25 < 43/10 < 13/3
4.25 = 4.25
43/10 = 4.3
13/3 = 4.33
4.25 < 4.3 < 4.33
The answer should be
f=1/5 x^2 + -2/5x
About one hundreds out of two hundred brobaly like literature better