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3 years ago

Tell whether the ratios form a proportion. 7 /16 2 /6 yes no

Mathematics

1 answer:

svlad2 [7]3 years ago

8 0

No they are have a great day

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Please help with this postulate! :)

atroni [7]

Answer:

C. ASA postulate

Step-by-step explanation:

<u>We observe two angles and the included side of ABC are congruent to two angles and the included side of DBE:</u>

∠A ≅ ∠D
∠C ≅ ∠ E
AC ≅ DE

This is called ASA

7 0

2 years ago

Read 2 more answers

5x + 4m = 43my + 6 solve for m

pav-90 [236]

9514 1404 393

Answer:

m = (5x -6)/(43y -4)

Step-by-step explanation:

Subtract 4m+6 to separate m-terms from other terms.

5x +4m -(4m +6) = 43my +6 -(4m +6)

5x -6 = 43my -4m

5x -6 = m(43y -4) . . . . factor out m

(5x -6)/(43y -4) = m . . . . divide by the coefficient of m

7 0

2 years ago

What is 50+_that equal420

snow_lady [41]

Answer:

370

Step-by-step explanation:

50 + x = 420

x = 420 - 50

x = 370

6 0

3 years ago

Read 2 more answers

Is (-2,-6) a solution of y < 7x + 8?

mojhsa [17]

Answer:

not a solution

Step-by-step explanation:

y < 7x + 8

Substitute (2-,-6) into the inequality

-6 < 7(-2) +8

-6 <-14+8

-6 <-6

This is not true because they are equal not less than

6 0

3 years ago

Read 2 more answers

(sin x)(tan x cos x - cot x cos x) = 1 - 2 cos2x

Aliun [14]

As

$\tan x=\dfrac{\sin x}{\cos x}$
$\cot x=\dfrac{\cos x}{\sin x}$

we have

$\sin x(\tan x\cos x-\cot x\cos x)=\sin x\left(\sin x-\dfrac{\cos^2x}{\sin x}\right)=\sin^2x-\cos^2x$

Recalling that $\cos2x=\cos^2x-\sin^2x$ , we end up with

$-\cos2x=1-2\cos2x$
$1=\cos2x$
$\implies2x=2n\pi$

(where $n$ is any integer)

$\implies x=n\pi$

5 0

3 years ago