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2 years ago

Simplify the following expression and write it in an exponential function form.

Mathematics

1 answer:

Sergio039 [100]2 years ago

7 0

Answer:

1/4 b^9

Step-by-step explanation:

(b^11 b^-7)/4b^-5

We know x^y * x^z = x^(y+z)

b^11 * b^ -7 = b^ (11-7) = b^4

(b^11 b^-7)/4b^-5

b^4 / 4 b^-5

We know x^y / x^z = x^(y-z(

b^4 / b^-5 = b^(4 - -5) = b^(4+5) = b^9

1/4 b^9

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Find the side length of a square whose area is 121 ft^2

kogti [31]

Answer:

The side length is 11 ft

Step-by-step explanation:

The area of a square is given by

A = s^2 where s is the side length

121 ft^2 = s^2

Take the square root of each side

sqrt( 121 ft^2) = sqrt(s^2)

11 ft = s

The side length is 11 ft

8 0

2 years ago

Read 2 more answers

Hey can someone please help, i dont know how to do this

yKpoI14uk [10]

Use the tenth’s theory and herons theory u will get it

6 0

2 years ago

Robert can paint a room in 6 hours. Julio can paint a room in 8 hours.how long will it take for the two of them to paint a room

Llana [10]

Roberto paints 1/6 of a room in 1 hour.
Julio paints1/8 of a room in 1 hour.

Working together, they paint (1/6 + 1/8) = (4/24 + 3/24) = 7/24 room per hour.

The reciprocal unit rate is 24/7 hour per room = <em>3-3/7 hours</em> per room.

6 0

3 years ago

[10 Points, Algebra 2]

tensa zangetsu [6.8K]

5/ 1+1= 5/2
1+4/1^2-3(1)-4= 5/-6

5/2 - 5/-6 does not equal zero

4 0

3 years ago

The weekly amount spent by a small company for in-state travel has approximately a normal distribution with mean $1450 and stand

Llana [10]

Answer:

0.0903

Step-by-step explanation:

Given that :

The mean = 1450

The standard deviation = 220

sample mean = 1560

$P(X > 1560) = P( Z > \dfrac{x - \mu}{\sigma})$

$P(X > 1560) = P(Z > \dfrac{1560 - 1450}{220})$

$P(X > 1560) = P(Z > \dfrac{110}{220})$

P(X> 1560) = P(Z > 0.5)

P(X> 1560) = 1 - P(Z < 0.5)

From the z tables;

P(X> 1560) = 1 - 0.6915

P(X> 1560) = 0.3085

Let consider the given number of weeks = 52

Mean $\mu_x$ = np = 52 × 0.3085 = 16.042

The standard deviation = $\sqrt {n \time p (1-p)}$

The standard deviation = $\sqrt {52 \times 0.3085 (1-0.3085)}$

The standard deviation = 3.3306

Let Y be a random variable that proceeds in a binomial distribution, which denotes the number of weeks in a year that exceeds $1560.

Then;

Pr ( Y > 20) = P( z > 20)

$Pr ( Y > 20) = P(Z > \dfrac{20.5 - 16.042}{3.3306})$

$Pr ( Y > 20) = P(Z >1 .338)$

From z tables

P(Y > 20) $\simeq$ 0.0903

7 0

3 years ago