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2 years ago

Simplify the following expression and write it in an exponential function form.

Mathematics

1 answer:

Sergio039 [100]2 years ago

7 0

Answer:

1/4 b^9

Step-by-step explanation:

(b^11 b^-7)/4b^-5

We know x^y * x^z = x^(y+z)

b^11 * b^ -7 = b^ (11-7) = b^4

(b^11 b^-7)/4b^-5

b^4 / 4 b^-5

We know x^y / x^z = x^(y-z(

b^4 / b^-5 = b^(4 - -5) = b^(4+5) = b^9

1/4 b^9

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Ben and Landon took turns driving on the recent 820 mile road trip Ben averaged 60 mph while Landon average 56 mph if the trip t

AysviL [449]

Answer:

9 hours

Step-by-step explanation:

Let :

Landon hours = x

Ben hours = y

x + y = 14 - - (1)

60x + 56y = 820 - - - (2)

From (1)

y = 14 - x

60x + 56(14 - x) = 820

60x + 784 - 56x = 820

4x = 820 - 784

4x = 36

x = 36/4

x = 9

Landon drove for 9 hours

4 0

2 years ago

PLSS help

GrogVix [38]

Answer: D, 1/12

Explanation:
Since it says how much MORE, we subtract. SO
3/4 - 2/3= 1/12

5 0

1 year ago

Read 2 more answers

F the range of the function f(x) = 7x – 2.7 is {14.1, 30.9, 41.4, 58.9, 68}, what is its domain?

grigory [225]

You need to solve 5 equations
1. 7x - 2.1 = 14.1
2. 7x - 2.1 = 30.9 and so on

1. 7x - 2.1 = 14.1
7x = 16.2
x = 2.314 so first number in the domain is 2.314

You can calculate the other 4 in the same way

7 0

2 years ago

Just give answers to blanck ones just give me The answers cause I don't want no explaining because I'm Savage

Airida [17]

Omg wow bruh #savageaf

6 0

3 years ago

Read 2 more answers

During an Apollo moon landing, reflecting panels were placed on the moon. This allowed Earth-based astronomers to shoot laser be

rusak2 [61]

Answer:

The distance between the astronomers and the moon was $7.56*10^{8]$ meters.

Step-by-step explanation:

We have that the speed is the distance divided by the time, so:

$v = \frac{d}{t}$

In this problem, we have that:

The reflected laser beam was observed by the astronomers 2.52 s after the laser pulse was sent. This means that $t = 2.52$ .

If the speed of light is 3.00 times 10^8 m/s, what was the distance between the astronomers and the moon?

We have that $v = 3*10^{8}$ m/s.

We have to find d. So:

$v = \frac{d}{t}$

$d = vt$

$d = 3*10^{8}*2.52$

$7.56*10^{8]$

The distance between the astronomers and the moon was $7.56*10^{8]$ meters.

7 0

3 years ago