The circumference of the circle is 75.36 cm.
Diameter of the circle is 24 cm,
- Step 2: Formula used and calculation:
Circumference of the circle is 
.
So, Radius, r = 24/2 = 12 cm.
Now, Putting the value in the above formula, we get
2 × 3.14 ×12 = 3.14 × 24 = 75.36 cm.
Hence, the circumference of the circle is 75.36 cm.
Learn more about circumference of the circle, refer:
brainly.com/question/23964435
Step-by-step explanation:
Since ,
Money lended =$400
Intetest =27.74%
Therefore,
Intetrst=p×r×t/100,if interested monthly
=400×27.74×1/100(interested monthly)
=4×27.74
=$110.96
Interest=p×r×t/100×1/12,if interested anually
=400×27.74×1/100/12
=110.96/12
=$9.24 or it will be $110.96 if it is interested anuaaly..
Answer: 10
use (PEMDAS)
P parentheses ()
E exponents
M multiplication • , () , x
D division
A addition +
S subtraction -
Explanation:
There are no parentheses.
There are exponents.
The multiplication is the exponents.
There is division.
There is addition and subtraction.
-how to solve-
First, do 2 to the second power and get 4.
Next, do 12-2+4 divided by 8.
Next do multiplication: there’s no more.
Next do division: you can’t do 4 divided by 8 so instead, do 12-2 = 10 plus 8.
Hope this helps!
Answer:
103= p small
plarge = 123
Step-by-step explanation:
We know that the the ratio of the areas is the scale factor squared/
Larger triangle over smaller triangle
72
----- = scale factor ^2
50
simplify by dividing by 2 on top and bottom
36
----- = scale factor ^2
25
Take the square root of each side
sqrt(36)
-------------- = sqrt(scale factor ^2)
sqrt(25)
6
-------------- = scale factor
5
The ratio of the perimeters is the scale factor
p large 6
-------------- = ----------------
p small 5
Using cross products
6 p large = 5 p small
We know the sum is 226
p large + p small = 226
p large = 226 - p small
We have 2 equation and 2 unknowns
6 p large = 5 p small
Substitute for p large
6 (226 - p small) = 5 p small
1356 - 6 p small = 5 p small
Add 6 p small to each side
1356 = 11 p small
divide by 11
1356/11 = p small
P large = 226-1356/11
p large = 2486/11-1356/11
plarge = 1130/11
The solution requires whole number answers so
1356/11 = p small
123.27 which rounds to 123
plarge = 1130/11
plarge = 102.7272 = 103
