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pashok25 [27]
2 years ago
5

I NEED HELP PEOPLE LAST TIME

Mathematics
1 answer:
Hoochie [10]2 years ago
3 0

29.

f(x) = -x^2-7x-6

As x \to \pm \infty, y \to - \infty.

This can be easily verified by looking at the graph (graph of a quadratic equation).

30.

The growth of a population is not linear, it's exponential.

31.

Exponential growth > polynomial, so y = 3^x.

35.

V(t) = 30\cdot (25)^{\frac{t}{20}}

The question is asking V(t) for t = 40.

V(40) = 30\cdot (25)^{\frac{40}{20}} \\~\\V(40) = 30\cdot 25^2 \\~\\V(40) = 30\cdot 625 \\~\\V(40) = 18750

36.

The point of symmetry of a quadratic equation y = ax^2+bx+c is at its vertice:

V_x = \dfrac{-b}{2a}

V_x = \dfrac{6}{2}

V_x = 3

The line is x= 3.

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Convert 123000000 milligram into gram​
velikii [3]

Answer:

123,000 grams

Step-by-step explanation:

1000 mg is equivalent to 1 gram.

3 0
2 years ago
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On the day that Tony was born his grandmother invested $2200 in a certificate of deposit that pays a 3% interest
galben [10]

Answer:

$3530.3541

Step-by-step explanation:

Given that:

Principal = 2200

Interest rate compounded annually (r) = 3%

Time (t) = 16 years

Using the compound interest formula :

A = P(1 + r/n)^n*t

A = final amount

n = number of times interest is applied per period

A = 2200(1 + 0.03)^16

A = 2200(1.03)^16

A = 2200 * 1.60470643909878751793

A = $3530.3541

Hence, amount in account on his 16th birthday will be $3530. 3541

3 0
3 years ago
Your reading material states that many banks pay interest that is calculated
Step2247 [10]
Carry on... There is not sufficient information to answer
3 0
3 years ago
A new test to detect TB has been designed. It is estimated that 88% of people taking this test have the disease. The test detect
Elodia [21]

Answer:

Correct option: (a) 0.1452

Step-by-step explanation:

The new test designed for detecting TB is being analysed.

Denote the events as follows:

<em>D</em> = a person has the disease

<em>X</em> = the test is positive.

The information provided is:

P(D)=0.88\\P(X|D)=0.97\\P(X^{c}|D^{c})=0.99

Compute the probability that a person does not have the disease as follows:

P(D^{c})=1-P(D)=1-0.88=0.12

The probability of a person not having the disease is 0.12.

Compute the probability that a randomly selected person is tested negative but does have the disease as follows:

P(X^{c}\cap D)=P(X^{c}|D)P(D)\\=[1-P(X|D)]\times P(D)\\=[1-0.97]\times 0.88\\=0.03\times 0.88\\=0.0264

Compute the probability that a randomly selected person is tested negative but does not have the disease as follows:

P(X^{c}\cap D^{c})=P(X^{c}|D^{c})P(D^{c})\\=[1-P(X|D)]\times{1- P(D)]\\=0.99\times 0.12\\=0.1188

Compute the probability that a randomly selected person is tested negative  as follows:

P(X^{c})=P(X^{c}\cap D)+P(X^{c}\cap D^{c})

           =0.0264+0.1188\\=0.1452

Thus, the probability of the test indicating that the person does not have the disease is 0.1452.

4 0
3 years ago
What is the equation of the line shown in this graph?
Vika [28.1K]

Answer:

y=1

Step-by-step explanation:

since there is no slope all you have is the y intercept so all you have to put is the y-intercept. That easy!

8 0
3 years ago
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