Answer:
5.625
Step-by-step explanation:
Step-by-step explanation:
Your problem → 5y+5/2 / 25y-20/40y^2-32y
5y+5/2÷25y-20/40y^2-32y
=5⋅y+5/2÷25×y-20/40×y^2-32×y
=5y+5/2÷25×y-20/40×y^2-32y
=5y+5/2×1/25×y-20/40×y^2-32y
=5y+y/10-20/40×y^2-32y
=5y+y/10-y^2/2-32y
=5y×10+y-y^2×5-32y×10 ÷ 10
=50y+y-5y2-320y ÷ 10
= -269y-5y^2 / 10
Answer:
no idea what to find would you please like to explain about this question
Let 
be the amount (gal) of the 40% slime solution you end up using. You want to end up with 120 gal of the 50% solution, so that you would use 
gal of the 70% solution.
You want the final solution to consist of 50% slime, or 60 gal of slime. Each gal of the 40% solution contributes 0.4 gal of slime, while each gal of the 70% solution contributes 0.7 gal of slime. This means
so the answer is B.
