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vagabundo [1.1K]
1 year ago
10

At the state fair, admission at the gate is $9. In addition, the cost of each ride is $3. Suppose that Deshaun will go on x ride

s. Deshaun wants the total number of dollars he spends on admission and rides to be at most t. Using the values and variables given, write an inequality describing this.

Mathematics
1 answer:
pshichka [43]1 year ago
4 0

SOLUTION:

Step 1:

In this question, we are given the following:

Step 2:

The details of the solution are as follows:

Step-by-step explanation:

Given :

At the state fair, admission at the gate is $9.

In addition, the cost of each ride is $3.

Suppose that Sam will go on x rides.

Then, cost of x rides ( in dollars) = Cost per ride x Number of rides

=3x

Total cost ( in dollars) : Admission fee + cost of x rides

= 9+3x

Sam wants the total number of dollars he spends on admission and rides to be at most t ( less than or equal to t )

9\text{ + 3x }\leq\text{ t}

CONCLUSION:

The final answer is:

Using the values and variables given, write an inequality describing this.​

9\text{ + 3x }\leq\text{ t}

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Jose has 9 more comic books than robin. robin has 5 more comic books than lee. if jose has 23 comic books, how many comic books
Lerok [7]
Simple subtraction. to find how many robin has, subtract 9 from 23, which is 14. so robin has 14 comic books. robin has 5 more than lee, so subtract 5 from 14, which is 9. so lee has 9 comic books
6 0
2 years ago
A force of 3 pounds is required to hold a spring stretched 0.6 feet beyond its natural length. how much work (in foot-pounds) is
ioda

The work done (in foot-pounds) in stretching the spring from its natural length to 0.7 feet beyond its natural length is 1.23 foot-pound

<h3>Data obtained from the question</h3>

From the question given above, the following data were obtained:

  • Force (F) = 3 pounds
  • Extension (e) = 0.6 feet
  • Work done (Wd) =?

<h3>How to determine the spring constant</h3>
  • Force (F) = 3 pounds
  • Extension (e) = 0.6 feet
  • Spring constant (K) =?

F = Ke

Divide both sides by e

K = F/ e

K = 3 / 0.6

K = 5 pound/foot

Thus, the spring constant of the spring is 5 pound/foot

<h3>How to determine the work done</h3>
  • Spring constant (K) = 5 pound/foot
  • Extention (e) = 0.7 feet
  • Work done (Wd) =?

Wd = ½Ke²

Wd = ½ × 5 × 0.7²

Wd = 2.5 × 0.49

Wd = 1.23 foot-pound

Therefore, the work done in stretching the spring 0.7 feet is 1.23 foot-pound

Learn more about spring constant:

brainly.com/question/9199238

#SPJ1

5 0
1 year ago
20 points+brainliest!
lakkis [162]

Answer:

C, D, E

Step-by-step explanation:

4 0
3 years ago
Behind my math class help pls
vladimir2022 [97]

Answer:

Please check the explanation.

Step-by-step explanation:

Part a)

Given that the two parallel lines are crossed by a transversal line.

Given that

m∠2 = 2x + 54 and m∠6 = 6x - 11

Angle ∠2 and ∠6 are corresponding angles.

Corresponding angles are congruent.

Thus,

m∠2 = m∠6

2x + 54 = 6x - 11

flipe the equation

6x - 11 = 2x + 54

subtract 2x from both sides

6x - 2x - 11 = 2x - 2x + 54

4x - 11 = 54

adding 11 to both sides

4x - 11 + 11 = 54 + 11

4x = 65

dvide both sides by 4

4x/4 = 65/4

x = 16.2500    (round to 4 decimal places)

Part b)

We have already determined

x = 16.2500

Given

m∠2 = 2x + 54

substitute x = 16.2500 in the euation

        = 2(16.2500) + 54

        = 86.5°

As angle ∠2 and angle ∠1 lie on a straight line. Hence, the sum of their angles must be 180°.

i.e.

m∠1 + m∠2 = 180°

substituting m∠2 =  86.5° in the equation

m∠1 + 86.5°  = 180°

subtracting 86.5° from both sides

m∠1 + 86.5° - 86.5° = 180° - 86.5°

m∠1 = 93.5°

Therefore, the measure of angle m∠1 is:

  • m∠1 = 93.5°
4 0
3 years ago
Select all of the following expressions that are equivalent to 16a+40 .
lina2011 [118]
The first one is true
<span>4(4a+10)  is 
</span>16 a + 40 after distribution

The second one is also true
<span>2(8a+20) 
16a + 40 after distribution

Third is not true
</span><span>4a(4+10a) 
</span><span>16a + 40a^2 after distribution

Last one is also true
</span><span>8(2a+5)
16a + 40 after distribution

Hope this helps :)</span>
5 0
3 years ago
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