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vfiekz [6]
3 years ago
15

Give the radian measure of an angle drawn in standard position that corresponds with the ray containing the coordinate point (−1

2, −3√2).
Mathematics
1 answer:
Sergeu [11.5K]3 years ago
5 0

Answer:

The radian measure of the angle drawn in standard position that corresponds with the ray containing the coordinate point (-12, -3\sqrt{2}) is approximately 1.108\pi radians.

Step-by-step explanation:

With respect to origin, the coordinate point belongs to the third quadrant, which comprises the family of angles from \pi\,rad to \frac{3\pi}{2}\,rad. The angle in standard position can be estimated by using the following equivalence:

\theta = \pi\,rad + \tan^{-1} \left(\frac{3\sqrt{2}}{12} \right)

\theta \approx \pi \,rad + 0.108\pi \,rad

\theta \approx 1.108\pi\,rad

The radian measure of the angle drawn in standard position that corresponds with the ray containing the coordinate point (-12, -3\sqrt{2}) is approximately 1.108\pi radians.

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Answer:

a)  Probability that exactly 1 fastener is defective, P(X = 1) = 0.144

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Step-by-step explanation:

a) Total number of fasteners = 120

Number of defective fasteners = 4

Probability of selecting a defective fastener, p = 4/120

p = 0.033

Probability of selecting an undefective fastener, q = 1 - p

q = 1 - 0.033

q = 0.967

5 fasteners were randomly selected, n =5

Probability that exactly one fastener is defective:

P(X =r) = (nCr) p^r q^{n-r}\\P(X =1) = (5C1) 0.033^1 0.967^{5-1}\\P(X =1) = 0.144

b) Number of gasoline outlets sampled, n = 900

Average gasoline price, \bar{x} = 4.113

Standard deviation, \sigma = 0.11

Confidence Level, CL = 95% = 0.95

Significance level, \alpha = 1 - 0.95 = 0.05

\alpha/2 = 0.05/2 = 0.025

From the standard normal table, z_{\alpha/2} = z_{0.025} = 1.96

error margin can be calculated as follows:

e_{margin} = z_{\alpha/2} * \frac{\sigma}{\sqrt{n} } \\e_{margin} = 1.96 * \frac{0.11}{\sqrt{900} }\\e_{margin} = 0.0072

The confidence interval will be given as:

CI = \bar{x} \pm e_{margin}  \\CI = 4.113 \pm 0.0072\\CI = [(4.113-0.0072), (4.113+0.0072)]\\CI = [4.1058, 4.1202]

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A service center receives an average of 0.6 customer complaints per hour. Management's goal is to receive fewer than three compl
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Answer:

0.18203 = 18.203% probability that exactly four complaints will be received during the next eight hours.

Step-by-step explanation:

We have the mean during a time-period, which means that the Poisson distribution is used to solve this question.

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

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x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given interval.

A service center receives an average of 0.6 customer complaints per hour.

This means that \mu = 0.6h, in which h is the number of hours.

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8 hours means that h = 8, \mu = 0.6(8) = 4.8.

The probability is P(X = 4).

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 4) = \frac{e^{-4.8}*4.8^{4}}{(4)!} = 0.18203

0.18203 = 18.203% probability that exactly four complaints will be received during the next eight hours.

5 0
3 years ago
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