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Zepler [3.9K]
3 years ago
14

What is 2.408 rounded to the nearest hundredth

Mathematics
1 answer:
frosja888 [35]3 years ago
8 0
The answer yo your question is 2.41
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Find the x-intercept of the line whose equation is 8x + 2y = 4.
horrorfan [7]

Answer: Hope this helps you

1/2

Step-by-step explanation:

<em>To find the x-int of any equation, you will need to replace the y with a 0 since when the x-int is when y is 0.</em>

8x+2y = 4 ➨ 8x+2*0 = 4

<em>Now I will do 2*0 which anything times 0 is equal to 0. And we are left with the equation of:</em>

8x = 4

<em>Now I will divide both sides by 8, which isolates our x.</em>

x = 1/2

The x-int is 1/2.

8 0
2 years ago
The newly elected president needs to decide the remaining 8 spots available in the cabinet he/she is appointing. If there are 14
Elanso [62]

Answer:

The members of the cabinet can be appointed in 121,080,960 different ways.

Step-by-step explanation:

The rank is important(matters), which means that the order in which the candidates are chosen is important. That is, if we exchange the position of two candidates, it is a new outcome. So we use the permutations formula to solve this quesiton.

Permutations formula:

The number of possible permutations of x elements from a set of n elements is given by the following formula:

P_{(n,x)} = \frac{n!}{(n-x)!}

If there are 14 eligible candidates for these positions (where rank matters), how many different ways can the members of the cabinet be appointed?

Permutations of 8 from a set of 14. So

P_{(14,8)} = \frac{14!}{(14-8)!} = 121,080,960

The members of the cabinet can be appointed in 121,080,960 different ways.

3 0
3 years ago
According to a​ survey, 60 ​% of the residents of a city oppose a downtown casino. Of these 60 ​% about 8 out of 10 strongly opp
katrin [286]

Answer:

(a) 0.48

(b) 0.20

(c) it is not unusual for a radomly selected resident to oppose the casino and strongly oppose the​ casino.

Step-by-step explanation:

​(a) Find the probability that a randomly selected resident opposes the casino and strongly opposes the casino. ​

The probability that a radomly selected resident opposes the casino and strongly opposes the cassino is the product of the two probabilities, that a resident opposes the casino and that it strongly opposes the casino (once it is in the first group) as it is shown below.

Use this notation:

  • Probability that a radomly selected resident opposes the casino: P(A)

  • Probability that a resident who opposes the casino strongly opposes it: P(B/A), because it is the probability of event B given the event A

i) Determine the <em>probability that a radomly selected resident opposes the casino</em>, P(A)

Probability = number of favorable outcomes / number of possible outcomes

  • P(A) is <em>given as 60%</em>, which in decimal form is 0.60

ii) Next, determine,the <em>probability that a resident who opposes the casino strongly opposes it</em>, P(B/A):

  • It is given as 8 out of 10 ⇒ P(B/A) = 8/10

iii) You want the probability of both events, which is the joint probability or  intersection: P(A∩B).

So, you can use the definition of conditional probability:

  • P(B/A) = P(A∩B) / P(A)

iv) From which you can solve for P(A∩B)

  • P(A∩B) = P(B/A)×P(A) =  (8/10)×(0.60) = 0.48

(b) Find the probability that a randomly selected resident who opposes the casino does not strongly oppose the casino.

In this case, you just want the complement of the probability that <em>a radomly selected resident who opposes the casino does strongly oppose the casino</em>, which is 1 - P(B/A) = 1 - 8/10 = 1 - 0.8 = 0.2.

​(c) Would it be unusual for a randomly selected resident to oppose the casino and strongly oppose the​ casino?

You are being asked about the joint probability (PA∩B), which you found in the part (a) and it is 0.48.

That is almost 0.50 or half of the population, so you conclude it is not unusual for a radomly selected resident to oppose the casino and strongly oppose the​ casino.

8 0
3 years ago
Solve the following system of equations and show all work. <br><br> y = -x^2 + 4<br> y = 2x + 1
Pavel [41]
-x^2 + 4 = 2x + 1
-x^2 - 2x + 4 - 1 = 0
-x^2 - 2x + 3 = 0
(x + 3)(-x + 1)= 0

x + 3 = 0           -x + 1 = 0
x = -3                -x = -1
                          x = 1

so x = -3 and x = 1
8 0
4 years ago
Plz someone help me.
satela [25.4K]
Hope this helps you! (and I'm right LOL)


5 0
3 years ago
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