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3 years ago

8

Use the space below to calculate the average monthly temperature in the Canadian tundra during the coldest months (October throu

gh May) and during the warmest months (June through September).

1 answer:

Illusion [34]3 years ago

3 0

Answer:

46

Step-by-step explanation:

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Dihsjsksiusjsueuuehehebdbbsjsshshshhs

il63 [147K]

is this a real question?

6 0

4 years ago

15% of a mass is 45 g. Calculate 20% of the mass

ira [324]

What is 100% of the mass ?

4 0

3 years ago

Read 2 more answers

Last week,the price of apples at a grocery store was 1.60 per pound.This week,apples at the same grocery store are on sale for a

Degger [83]

Answer:

The total price of $4\frac{1}{2}$ pounds of apples is <u>$6.48</u>.

Step-by-step explanation:

Given:

Last week,the price of apples at a grocery store was 1.60 per pound.This week,apples at the same grocery store are on sale for a 10% discount.

Now, to find the total price of 4 1/2 pounds of apples this week at the grocery store.

The price of apples at a grocery store last week was = $1.60 per pound.

This week apples at the same grocery store is on sale of 10% discount.

Thus, the price of apples at a grocery store this week is:

$1.60-10\%\ of\ 1.60.$

$=1.60-\frac{10}{100} \times 1.60$

$=1.60-0.16$

$=\$1.44.$

So, the price of apples per pound this week is $1.44.

Now, to get the total price of $4\frac{1}{2}$ pounds of apples by using unitary method:

If 1 pound of apples cost = $1.44.$

Then, $\frac{9}{2}$ pound of apples cost = $1.44\times \frac{9}{2}$

$=1.44\times 4.5$

$=\$6.48.$

Therefore, the total price of $4\frac{1}{2}$ pounds of apples is $6.48.

4 0

3 years ago

What is the answer for 7x minus x

larisa86 [58]

$\bf{7x-x}$

We can take out x as a factor

$\bf{x(7-1}$

What is 7-1=?

6 !

So then that means

$\bf{x(6)=6x}$

So your final answer is

$\boxed{\bf{6x}}$

8 0

4 years ago

Read 2 more answers

find two consecutive odd integers whose product is 1 less than 6 times their sum. Domain for the smallest : {-1, 1, 11}

inn [45]

Let x be the 1st odd number, and x+2 the second odd consecutive number:

(x)(x + 2) = 6[((x) + (x+2)] -1
x² + 2x = 6(2x + 2) - 1

x² + 2x = 12x +12 - 1
And x² - 10x - 11=0

Solve this quadratic expression:

x' = [+10 +√(10²- 4.(1)(-11)]/2 and x" = [+10 -√(10²- 4.(1)(-11)]/2

x' = [10 + √144]/2 and x" = [10 - √64]/2

x' = (10+12)/2 and x" = (10-12)/2

x = 11 and x = -1

We have 2 solutions that satisfy the problem:

1st for x = 11, the numbers at 11 and 13
2nd for x = - 1 , the numbers are -1 and +1
If you plug each one in the original equation :(x)(x + 2) = 6[((x) + (x+2)] -1
you will find that both generates an equlity

6 0

3 years ago