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saveliy_v [14]
3 years ago
9

Classify the following triangle. Check all that apply.

Mathematics
1 answer:
Schach [20]3 years ago
3 0

Answer:

E and F

Step-by-step explanation:

✔️One of the angles of the triangle given has a measure that is above 90° (120°). An obtuse triangle triangle has an angle measure that is above 90°. Therefore, the triangle above is an obtuse triangle.

✔️All three angles and sides are of unequal measure, therefore, this can be referred to as a scalene triangle. A scalene triangle has 3 unequal angles.

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What is the radius of a circle with a circumference of 36(3.14) cm
mart [117]
It should be 18, because despite of 3,14, because that's pi and radius is half of the diameter, so36 divide 2 is 18.
6 0
3 years ago
Calculate the area of triangle .
AnnZ [28]

Answer:

20 units

Step-by-step explanation:

The formula for the area:

A = bh × 1/2

B = 8 units

H = 5 units

8 × 5 = 40

40 × 1/2 = 20

8 0
3 years ago
What is the solution of the equation n/10 = 7?<br><br>n= ____​
ozzi

Answer:

n = 70

Step-by-step explanation:

n/10 = 7

Multiply each side by 10

n/10 *10 = 7*10

n = 70

3 0
3 years ago
Read 2 more answers
find the angle between the vectors. (first find the exact expression and then approximate to the nearest degree. ) a=[1,2,-2]. B
SashulF [63]

Answer:

\theta = cos^{-1} (\frac{10}{\sqrt{9} \sqrt{25}})=cos^{-1} (\frac{10}{15}) = cos^{-1} (\frac{2}{3}) = 48.190

Since the angle between the two vectors is not 180 or 0 degrees we can conclude that are not parallel

And the anfle is approximately \theta \approx 48

Step-by-step explanation:

For this case first we need to calculate the dot product of the vectors, and after this if the dot product is not equal to 0 we can calculate the angle between the two vectors in order to see if there are parallel or not.

a=[1,2,-2], b=[4,0,-3,]

The dot product on this case is:

a b= (1)*(4) + (2)*(0)+ (-2)*(-3)=10

Since the dot product is not equal to zero then the two vectors are not orthogonal.

Now we can calculate the magnitude of each vector like this:

|a|= \sqrt{(1)^2 +(2)^2 +(-2)^2}=\sqrt{9} =3

|b| =\sqrt{(4)^2 +(0)^2 +(-3)^2}=\sqrt{25}= 5

And finally we can calculate the angle between the vectors like this:

cos \theta = \frac{ab}{|a| |b|}

And the angle is given by:

\theta = cos^{-1} (\frac{ab}{|a| |b|})

If we replace we got:

\theta = cos^{-1} (\frac{10}{\sqrt{9} \sqrt{25}})=cos^{-1} (\frac{10}{15}) = cos^{-1} (\frac{2}{3}) = 48.190

Since the angle between the two vectors is not 180 or 0 degrees we can conclude that are not parallel

And the anfle is approximately \theta \approx 48

3 0
3 years ago
How to simplify this expression??
sdas [7]

Answer :

1

Step-by-step-explanation :

{x}^{2}  + 4x + 5 -  {(x + 2)}^{2}  \\  {x}^{2}  + 4x + 5 - ( {x}^{2}  + 4x + 4)   \\

{x}^{2}  + 4x + 5 -  {x}^{2}  - 4x - 4 =  {x}^{2}  -  {x}^{2}  + 4x - 4x + 5 - 4 = 5 - 4 = 1

8 0
3 years ago
Read 2 more answers
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