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Law Incorporation [45]
3 years ago
15

Bamboo Plant A is 1.2 meters tall and growing at a rate of 0.45 meter per day. Bamboo Plant B is 0.85 meter tall and growing 0.5

meter per day. After how many days will Plant B be taller than Plant A?
Mathematics
1 answer:
pashok25 [27]3 years ago
3 0

Answer:

7 days

Step-by-step explanation:

Bamboo plant A = 1.2 + 0.45d

Bamboo plant B = 0.85 + 0.5d

Where,

d = number of days

Equate the two growth

Bamboo plant A = Bamboo plant B

1.2 + 0.45d = 0.85 + 0.5d

Collect like terms

1.2 - 0.85 = 0.5d - 0.45d

0.35 = 0.05d

Divide both sides by 0.05

d = 0.35 / 0.05

d = 7 days

Plant B be taller than Plant A after 7 days

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Which decimal is greater 0.7 or 0.07?
Radda [10]

Answer:

0.7

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A= πr2
d=10m
2r=d
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A=3.14 •25
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7 0
3 years ago
You drive 30 miles due east in a half hour. Then, you turn left and drive 30 miles north in 1 hour. What are your average speed
garri49 [273]
Original position: P1=(0,0)
<span>You drive 30 miles due east in a half hour: x=+30 miles, t1=1/2 hour=0.5 hours
</span><span>Then, you turn left and drive 30 miles north in 1 hour: y=+30 miles, t2=1 hour
Rectangular coordinates of final position: P2=(x,y)→P2=(30,30)
Total time: t=t1+t2=0.5 hours+1 hour→t=1.5 hours

Average speed: S ave=d/t
Total distance: d=x+y=30 miles+30 miles→d=60 miles
S ave = 60 miles / (1.5 hours)
S ave = 40 miles/hour

Velocity is a vector, the magnitude of this vector is the magnitude of the vector of change of position dividing by the total time t
The vector of change of position: s=P1-P2=(30,30)-(0,0)=(30-0,30-0)→
s=(30,30) 
Magnitude of vector s=sqrt[30^2+30^2]=sqrt[30^2*2]=sqrt[30^2]*sqrt(2)
Magnitude of vector s=30*sqrt(2) miles

Magnitude of velocity vector = Magnitud of vector s / t
Magnitude of velocity vector = [30*sqrt(2) miles] / (1.5 hours)
Magnitude of velocity vector = 20*sqrt(2) miles / hour
Magnitude of velocity vector=20*1.4142 miles / hour
Magnitude of velocity vector=28.284 miles/hour

Polar coordinates of your position=(r, theta)
r=Magnitude of vector s=30*sqrt(2) miles
theta=tan^(-1) (y/x) = tan^(-1) [(30 miles) / (30 miles)]
theta=tan^(-1) (1)→theta=45°=Pi/4 (Pi=3.1416)
Polar coordinates of your position: ( 30*sqrt(2) miles, 45°)
Polar coordinate of your position: ( 30*sqrt(2) miles, Pi/4 )

Answers:
Average speed: 40 miles / hour
Velocity: 20*sqrt(2) miles / hour = 28.284 miles / hour
Rectangular coordinates of your position = (30,30)
Polar coordinates of your position=(30*sqrt(2) miles,45°)
Polar coordinates of your position=(30*sqrt(2) miles,Pi/4)</span>
4 0
3 years ago
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