Answer:
The probability that a randomly selected passenger car gets more than 37.3 mpg is 0.1587.
Step-by-step explanation:
Let the random variable <em>X</em> represent the miles-per-gallon rating of passenger cars.
It is provided that
.
Compute the probability that a randomly selected passenger car gets more than 37.3 mpg as follows:


Thus, the probability that a randomly selected passenger car gets more than 37.3 mpg is 0.1587.
Box 1) (LxW) 20x6=120
box 2) (LxW) 15x4=60
box 1 cost) (size of box x price of box) 120x1.25=150
box 2 cost) (size of box x price of box) 60x1.25=75
subtract 150 and 75 to get 75
answer: the company is saving $75 by choosing to make 50 of box 2 instead of 50 of box 1
hope this makes sense comment if you need more explanation
Answer:
B 10x+5
Step-by-step explanation:
:)