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andrew11 [14]
3 years ago
5

Suppose the class sizes in high schools in a major public school district are normally distributed with an unknown population me

an and standard deviation. If a random sample of 28 high school classes is taken to estimate the mean class size, use a calculator to find the t-score that should be used to find a 90% confidence interval estimate for the population mean.
Mathematics
1 answer:
Blizzard [7]3 years ago
4 0

Answer:

1.703

Step-by-step explanation:

The reason we try to find t score is because the sample size is below 30, meaning the sample size is small

Hence:

Step 1

We find the degree of freedom

The Degrees of freedom = Number of samples - 1

The random number of samples = 28

= 28 - 1

= 27

Step 2

Using a t score table or t score calculator, we can obtain the t score value for a 90% confidence interval and degree of freedom of 27

90% confidence interval =

10% significance level = 0.10 for two tails or 0.1/2 = 0.05 for one tail

Hence: t90 = 1.703

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Answer:

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Step-by-step explanation:

Consider expression x^2+y^2-9x+10y+15=0.

First, form perfect squares:

(x^2-9x)+(y^2+10y)+15=0,\\ \\\left(x^2-9x+\dfrac{81}{4}\right)-\dfrac{81}{4}+(y^2+10y+25)-25+15=0,\\ \\\left(x-\dfrac{9}{2}\right)^2+(y+5)^2=10+\dfrac{81}{4},\\ \\\left(x-\dfrac{9}{2}\right)^2+(y+5)^2=\dfrac{121}{4}.

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6 0
3 years ago
Round 1.6 to the nearest whole number
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Answer:

The Answer is 2

Step-by-step explanation:

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3 years ago
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An economist wants to estimate the mean per capita income (in thousands of dollars) for a major city in California. Suppose that
sergiy2304 [10]

Answer:

(22.0297, 23.3703)

Step-by-step explanation:

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Mean = 22.7

n = 183

Population std dev = 6.3

Since population std dev is known we can use Z critical value.

Std error = \frac{6.3}{\sqrt{183} } \\=0.4657

Z critical =1.44

Marginof error = ±1.44*0.4657=0.6706

Confidence interval 85%

=(22.7-0.6703, 22.7+0.6703)\\= (22.0297, 23.3703)

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How do i put 1/6 2/5 3/5 and 3/7 from least to greatest
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3/5 1/6 3/7 2/5
------------------------
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