I'd say the first or third one, however, I'm not too sure:)
Speed of the ship in the second hour = (62.5 * x ) / 100 kph.
In third hour it is [(62 * x) / 100 ] * x/100]
is 4th hour its is the above * x/100 again so we can now form the equation
62.5x x x
------- * ---- * ---- = 32
100 100 100
62,5 x^3 = 32,000,000
x^3 = 512,000
x = 80 <----- Answer to (a)
(b) Ship travels 62.5 in first hour then this falls by a common ratio of 0.8 each hour so we have a geometric sequence
Dist travelled in 6 hours = a1 1 - r^n
-------- = 62.5* (1 - 0.8^6) / 1 -0.8 = 230.56
1 - r
Answer is 230.56 km
Answer:
m+n=54 and m=3n+8 is the system of equations that could be used to determine the price of each book.
Step-by-step explanation:
Given,
Total cost of maths book and novel = $54
Let,
Cost of maths book = m
Cost of novel = n
According to given statement;
m+n=54 Eqn 1
the price of the math textbook, m, is $8 more than 3 times the price of the novel
m = 3n+8 Eqn 2
m+n=54 and m=3n+8 is the system of equations that could be used to determine the price of each book.
Step-by-step explanation:
A=3
B=4
C=5
Substitute 3 in for 'a' in the equation, and 5 in for 'c' in the equation to get 17.
