Completely random design is used in this experiment.
In the given question,
A business wants to investigate the efficacy of a novel painkiller.
100 participants who suffer from chronic discomfort are enlisted.
Each participant takes the brand-new painkiller for two weeks before switching to a placebo for an additional two weeks.
The order of the tablets is chosen at random for each participant, and the subjects are unaware of which pill contains the actual medication.
Each subject's variance in total pain will be measured by researchers.
We have to check what type of experiment design is this.
As we can see in the question that they recruit 100 volunteers with chronic pain and each subject they use new pain relief medicine for a 2-week period and a placebo for another 2-week period.
They assign each subject randomly.
As we know that in a completely random design, treatments are randomly assigned to sampling material. The usual method for doing this is to make a list of the treatments and give each one a random number.
So we can see that completely random design is used in this experiment.
To learn more about Completely random design link is here
brainly.com/question/17128981
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The total number of people that will be selected is 14.
<u>Step-by-step explanation:</u>
For stratified random sampling at first we need to divide the population into some strata and then choose sample from each. For the given problem the response category is
Sample size of strata = (Size of entire sample by populaion size) multiply strata size
= (20 by 300) multiply 210
after solving we get, 14
therefore, 14 people will be selected.
One merit is that here since we divide the whole data into stratas and then select samples from that so it can be used as a guard against unwanted samples and also gives more accurate sample measure. Here since we required samples from the population who gave yes and no opinion so it is better to use stratified sampling method otherwise if we use simple random sampling then we may choose those samples who gave no opinion. But since we don't use that method so we can avoid this.
At least 5 coins are required:
50¢
25¢
10¢
10¢
1¢
-2 1/3 - (- 10 1/6) =
- 7/3 + 61/6 =
-14/6 + 61/6 =
47/6....or 7 5/6
